Part A.
Using the Pythagorean theorem,
PR² = PQ² +QR²
PR² = (14 ft)² +(6 ft)² = 196 ft² +36 ft² . . . . substitute the given numbers
PR² = 232 ft² . . . . . . . . . . . . . . . . . . . . . . . .find the sum
PR = √(232 ft²) ≈ 15.23 ft . . . . . . . . . . . . . take the square root
The length of rod PR is 15.23 ft.
Part B.
Using the Pythagorean theorem,
PR² = PQ² +QR²
(16 ft)² = (14 ft)² +QR² . . . . . . . substitute the given numbers
256 ft² -196 ft² = QR² . . . . . .. subtract 14²
60 ft² = QR² . . . . . . . . . . . . . . find the sum
√(60 ft²) = QR ≈ 7.75 ft . . . . . take the square root
The new height QR is about 7.75 ft.
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Goodluck!
God Bless you!!!
I believe the equation is
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
In this case, you would simplify it by adding them together.
=
![10 \sqrt[4]{2x}](https://tex.z-dn.net/?f=10%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
And can even be changed to an exponential equation:
