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4 years ago

Does the point (–3, 2) lie inside, outside, or on a circle with center (4, 0) and radius 5 units?

Mathematics

1 answer:

anastassius [24]4 years ago

8 0

Answer:

The point (-3, 2) lies outside of the circle centered at (4, 0) with radius 5.

Step-by-step explanation:

The distance between two points (x₁, y₁) and (x₂, y₂) on the x-y plane can be calculated with:

√((x₁ - x₂)² + (y₁ - y₂)²)

So in this case, with the points (-3, 2) and (4, 0), the distance is:

√((-3 - 4)² + (2 - 0)²)

√(49 + 4)

√(53) ≈ 7.28

Since 7.28 > 5, the point (-3, 2) lies outside of the circle centered at (4, 0) with radius 5.

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Which equation is the direct variation equation if f(x) varies directly with x and f(x)=-18 when x=3

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3 years ago

An oil tanker empties at 3.5 gallons per minute. Convert this rate to cups per second. Round to the nearest tenth.

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4 years ago

What is the slope of the line shown below? A. -5 B. 5 C.-2 D. 2

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3 years ago

A bucket of paint has spilled on a tile floor. The paint flow can be expressed with the function p(t) = 6t, where t represents t

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Answer:

A) A[p(t)] = 36πt²

B) 7234.56 square units

Step-by-step explanation:

Given functions:

$\begin{cases}p(t)=6t \\ A(p)=\pi p^2 \end{cases}$

Part A

To find the area of the circle of spilled paint as a function of time, substitute the function p(t) into the given function A(p):

$\begin{aligned}A(p) & = \pi p^2\\\\ \implies A[p(t)] & = \pi [p(t)]^2\\& = \pi (6t)^2\\& = \pi 6^2 t^2\\& = 36\pi t^2\end{aligned}$

Part B

Given

t = 8 minutes
π = 3.14

Substitute the given values into the equation for A[p(t)} found in part A:

$\begin{aligned}A[p(8)] & = 36\pi t^2\\& = 36 \cdot 3.14 \cdot 8^2\\& = 36 \cdot 3.14 \cdot 64\\& = 113.04 \cdot 64\\& = 7234.56\:\: \sf square\:units\end{aligned}$

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