Answer:
The point (-3, 2) lies outside of the circle centered at (4, 0) with radius 5.
Step-by-step explanation:
The distance between two points (x₁, y₁) and (x₂, y₂) on the x-y plane can be calculated with:
√((x₁ - x₂)² + (y₁ - y₂)²)
So in this case, with the points (-3, 2) and (4, 0), the distance is:
√((-3 - 4)² + (2 - 0)²)
√(49 + 4)
√(53) ≈ 7.28
Since 7.28 > 5, the point (-3, 2) lies outside of the circle centered at (4, 0) with radius 5.
