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2 years ago

Segment Addition Postulate ( help )

Mathematics

1 answer:

Komok [63]2 years ago

4 0

Answer:

x = 13

Step-by-step explanation:

NM + ML + LK = x - 6 + 9 + 2x - 19

NK = 23

x - 6 + 9 + 2x - 19 = 23

3x - 16 = 23

3x = 39

x = 13

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If this fish tank is filled only halfway, how much water will it hold?

Morgarella [4.7K]

Answer:

I believe you typed your final answer choice incorrectly, as it should read 960 which is the correct answer

Step-by-step explanation:

the volume is 1920

1920/2=960

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2 years ago

A toy box has a volume of 30 cubic feet. It is 5 feet wide And 2 feet long. What is the height of the toy box

otez555 [7]

V = a * b * c
V = 30
a = 5
b = 2
c = ?
30 = 5*2*c
30 = 10*c
c = 30/10 = 3
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2 years ago

Read 2 more answers

Determine whether is a right triangle for the given vertices. Explain. Q(7, –10), R(–3, 0), S(9, –8)

andriy [413]

Answer:

Yes, It is a right triangle for the given vertices.

Step-by-step explanation:

Given:

Q(7, –10),

R(–3, 0),

S(9, –8)

To Find:

determine whether is a rig ht triangle for the given vertices = ?

Solution:

QR= $\sqrt{(-3-7)^2+(0-(-10))^2}$

QR= $\sqrt{(-10)^2+(10)^2}$

QR= $\sqrt{100+100}$

QR= $\sqrt{200}$ --------------------------(1)

QR=14.142136

RS= $\sqrt{(9-(-3))^2+(-8-0)^2}$

RS= $\sqrt{(12)^2+(-8)^2}$

RS= $\sqrt{144+64}$

RS= $\sqrt{208}$ ---------------------------(2)

RS=14.422205

QS= $\sqrt{(7-9)^2+(-10-(-8))^2}$

QS= $\sqrt{(-2)^2+(-2)^2}$

QS= $\sqrt{4+4}$

QS= $\sqrt{8}$ -------------------------------------(3)

QS=2.828427

According to Pythagorean Theorem,

$RS^2 = QR^ +QS^2$

Substituting the values,

$(\sqrt{208})^2 = (\sqrt{200})^2 +(\sqrt{8})^2$

$208 = 200 +8$

208 = 208

Pythagorean theorem is satisfied. Hence it is a right triangle.

8 0

2 years ago

HELP ASAP

Shkiper50 [21]

Answer:

The volume is 192

Step-by-step explanation:

Multiply the bottom numbers which are 2, 2, 6, 4, and 2.

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2 years ago

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The formula for the volume of a sphere is. What is the formula solved for r?

nataly862011 [7]

Answer:

$r = \sqrt[3]{\dfrac{3V}{4 \pi}}$

Step-by-step explanation:

$V = \dfrac{4}{3}\pi r^3$

$\dfrac{4}{3}\pi r^3 = V$

$\pi r^3 = \dfrac{3V}{4}$

$r^3 = \dfrac{3V}{4 \pi}$

$r = \sqrt[3]{\dfrac{3V}{4 \pi}}$

3 0

2 years ago