The width of the cooling tower at the base of the structure will be A. 36 meters.
<h3>How to calculate the width?</h3>
From the information given, the towers walls are modeled by x²/324 - (y² - 90)²/1600.
Therefore, the width of the cooling tower at the base of the structure will be:
= 2 × ✓324
= 2 × 18
= 36
In conclusion, the width is 36 meters.
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Answer:
651.
Step-by-step explanation:
Note: In the given series it should be -29 instead of 29 because 29 cannot be a term of AP whose first term is 91 and common difference is -6.
Consider the given series is
It is the sum of an AP. Here,
First term = 91
Common difference = 85 - 91 = -6
Last term = -29
nth term of an AP is
where, a is first term and d is common difference.
Sum of AP is
Therefore, the sum of given series is 651.
Step-by-step explanation:
- 8 (3n - 5) \\ - 24n + 40 \\ please \: give \: full \: question \\
Answer:
y=(9a^2-1)x-6a^3+2
Step-by-step explanation:
11 blocks can be carried at a time
Hope this helps :)