Answer:
2 + 3i, midpoint is (2,3)
Step-by-step explanation:
we need to find the midpoint between (-1+9i) and B=(5-3i)
To find the midpoint of two points (a+bi) and (c+di) in a complex plane,
we apply formula

A = (-1+9i) and B=(5-3i)
Midpoint for AB is


2 + 3i , so midpoint is (2,3)
The angles of a triangle always add up to 180°.
120 + x + 16 + x = 180
Add up the values.
136 + 2x = 180
Subtract 136 from both sides.
2x = 44
Divide both sides by 2.
x = 22
This is an interesting question. I chose to tackle it using the Law of Cosines.
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355
Answer:
hope this helps
Step-by-step explanation:
x > −5