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2 years ago

Twice a number x exceed 5 at least by 4. find the possible value of x.

Mathematics

2 answers:

jeyben [28]2 years ago

6 0

Answer:

$x \ge 4.5$

Step-by-step explanation:

The number 2x is larger than 5, so 2x - 5 is the difference between 2x and 5. This difference is at least (greater than or equal to) 4.

$2x-5 \ge 4\\\\2x \ge 9\\\\x \ge 4.5$

salantis [7]2 years ago

5 0

Answer:

Step-by-step explanation:

2x › 5 (buy at least 4)

so you can just start plugging numbers in.

I used 5, 5 times 2 is 10 which is 5 more that 5, which does met the quota.

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5 + 3x - 2 for in the simplest form

emmasim [6.3K]

Answer:

3x +3

Step-by-step explanation:

5 + 3x - 2

Combine like terms

3x +5-2

3x +3

8 0

2 years ago

Read 2 more answers

I got letter C as my answer, is that correct?

lisov135 [29]

Yes it is C if you do the math and simplify it that is what you’ll get

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2 years ago

Name the postulate or theorem you can use to prove the triangles congruent

Lesechka [4]

Answer:

ASA

Step-by-step explanation:

if you understood the other, similar questions now, this one is really, really easy.

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so, angle side angle or ASA

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2 years ago

it took Bob 55 minutes to clean the garbage. How many seconds did it take bob?there are 60 seconds in one minute please help me

defon

Answer:

3,300 sec

Step-by-step explanation:

7 0

2 years ago

(10.02)

melisa1 [442]

Answer:

$sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}$

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

$Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}$

Therefore:

$sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}$

$cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}$

$Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}$

4 0

2 years ago