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Alex777 [14]
3 years ago
7

A roof on a castle tower is shaped like a cone with a diameter of 12 feet and has a slant height of 13 feet one bundle of Shingl

es covers 32 ft.² how many bundles should you buy to cover the roof
Mathematics
1 answer:
marissa [1.9K]3 years ago
8 0

Answer:

  8

Step-by-step explanation:

The lateral area of a cone is ...

  LA = (π/2)ds

where d is the diameter, and s is the slant height.

The area of this tower roof is about ...

  LA = (π/2)(12 ft)(13 ft) = 78π ft² ≈ 245 ft²

About 245/32 = 7.7 bundles of shingles will be required for coverage.

You should buy 8 bundles of shingles to cover the roof.

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chubhunter [2.5K]
Well, if the pinwheels cost $1 each, then 10 dimes is what it would take to pay for them. 10 dimes = 1 dollar, because a dime has a value of 10 cents and 10 times 10 = 100, and there is 100 cents in a dollar.
4 0
3 years ago
At a store, carpet is sold in units of 10 square yards.
Sliva [168]
We can generalise this by finding the equation of the line.
The gradient is: 15

We can take when x = 10, and y = 150 to find the equation of the line.
y - 150 = 15(x - 10)
y - 150 = 15x - 150
y = 15x

Thus, when x = 80, y = $1200 (ie B)
6 0
3 years ago
There are 16 peices of fruit in a bowl and 12 of them are apples. What percentage of the pieces of fruit in the bowl are apples?
valentina_108 [34]

Answer: if you simplify 12/16 to 3/4 then you multiply that fraction by 25 you get 75/100 which translates to 75%.

5 0
3 years ago
Two vertical poles of heights 60 ft and 80 ft stand on level ground, with their bases 100 ft apart. A cable that is stretched fr
Andreyy89

Answer:

Step-by-step explanation:

Given

height of two Poles are 60 and 80 ft

Distance between them is 100 ft

Let x be the distance of Pole of ht 80 ft from Point of stretch

thus length of rope is given by

L=L_1+L_2

L_1=\sqrt{80^2+x^2}

L_2=\sqrt{60^2+(100-x)^2}

L=\sqrt{80^2+x^2}+\sqrt{60^2+(100-x)^2}

differentiate w.r.t x we get

\frac{\mathrm{d} L}{\mathrm{d} x}=\frac{2x}{2\sqrt{80^2+x^2}}-\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}

Put \frac{\mathrm{d} L}{\mathrm{d} x}=0 to get minimum value

\frac{2x}{2\sqrt{80^2+x^2}}=\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}

squaring

x^2\left ( (100-x)^2+60^2\right )=(100-x)^2(80^2+x^2)

Rearranging

28x^2-1800x+640000=0

x=\frac{400}{7}

thus L_1=98.312 ft

L_2=73.73 ft

L=172.04 ft  

7 0
3 years ago
Which algebraic expression is equivalent to the expression below?
Anna007 [38]

Answer:

\boxed {52x - 45} (Choice B)

Step-by-step explanation:

Solve the following expression:

9(5x - 5) + 7x

-Use <u>Distributive Property</u>:

9(5x - 5) + 7x

45x - 45 + 7x

-Combine like terms:

45x - 45 + 7x

\boxed {52x - 45}

6 0
4 years ago
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