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sergeinik [125]
2 years ago
14

I need help with the car questions. Pls it’s due in 10 minutes

Mathematics
1 answer:
Natasha_Volkova [10]2 years ago
3 0

Answer:

1250 7500 3

Step-by-step explanation: im just smart

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Factor the quadratic expression in the equation y=2x^2+28x+96 and use the factors to find the zeros of the equation. Then, use t
gavmur [86]

Answer:

x=-7

Step-by-step explanation:

We have been given an equation y=2x^2+28x+96. We are asked to find the zeros of equation by factoring and then find the line of symmetry of the parabola.

Let us factor our given equation as:

2x^2+28x+96=0

Dividing both sides by 2:

x^2+14x+48=0

Splitting the middle term:

x^2+6x+8x+48=0

(x^2+6x)+(8x+48)=0

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(x+8)(x+6)=0

Using zero product property:

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x+8=0\text{ (or) }x+6=0

x=-8\text{ (or) }x=-6

Therefore, the zeros of the given equation are x=-8\text{ (or) }x=-6.

We know that the line of symmetry of a parabola is equal to the x-coordinate of vertex of parabola.

We also know that x-coordinate of vertex of parabola is equal to the average of zeros. So x-coordinate of vertex of parabola would be:

\frac{-8+(-6)}{2}=\frac{-14}{2}=-7

Therefore, the equation x=-7 represents the line of symmetry of the given parabola.

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