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kipiarov [429]
3 years ago
15

Place the numbers 40 and 100 into the proportion. (Whole)(percents) ----------- (Part) what goes where?

Mathematics
1 answer:
Ksivusya [100]3 years ago
4 0

Answer:

Step-by-step explanation:

Hard to tell how the question should read.

40/100 = 40%

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your basketball team made 10 three pointers 8 two pointers and 12 one point foul shots your openents made 8 three pointers 12 tw
inn [45]

Answer:

The opponents won by 1 points

Step-by-step explanation:

Your team (10*3)+(8*2)+(12*1)=58

Opponents (8*3)+(12*2)+(11*1)=59

8 0
3 years ago
At over 15 million degrees Celsius, the temperature of the sun's core is high
Lilit [14]
Nuclear fusion is the answer
7 0
3 years ago
Kareem purchased several packs of gum to place in gift baskets for $1.26 each. He spent a total of $8.82. How many packs of gum
777dan777 [17]

Answer: 7 packs of gum.

Step-by-step explanation:

If the total amount of the purchase is $8.82 and the individual price is $1.26, to find out how many packs Kareem purchased, we need to divide the total amount spent ($8.82) by the amount of each pack ($1.26), so:

8.82 ÷ 1.26 = 7

So, Kareem bought 7 packs of gum.

5 0
4 years ago
A certain forest covers an area of
iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

if

4500 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year  4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year  5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year  6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0
3 years ago
Help please! Please put the answers numbered!
Nesterboy [21]
1: ‘8’/3x = 1+ 5/3x
2: ‘8’/3x-5/3x= 1+ 5/3x-‘5/3x’
3: ‘3’/3x=1
4: 1
4 0
3 years ago
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