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Goryan [66]
4 years ago
14

Kareem purchased several packs of gum to place in gift baskets for $1.26 each. He spent a total of $8.82. How many packs of gum

did he buy?
Mathematics
1 answer:
777dan777 [17]4 years ago
5 0

Answer: 7 packs of gum.

Step-by-step explanation:

If the total amount of the purchase is $8.82 and the individual price is $1.26, to find out how many packs Kareem purchased, we need to divide the total amount spent ($8.82) by the amount of each pack ($1.26), so:

8.82 ÷ 1.26 = 7

So, Kareem bought 7 packs of gum.

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If 64 is added to a number, the result is 40 less than three times the number. Find the number.
damaskus [11]

Answer:

52

Step-by-step explanation:

Let the required number be x.

According to the given description:

x + 64 = 3x - 40

64 + 40 = 3x - x

104 = 2x

x = 104/2

x = 52

Thus, the required number is 52.

8 0
3 years ago
Dante is selling donuts outside a huge office building every morning. The first week
inysia [295]

Answer:

<h2>$205</h2>

Step-by-step explanation:

45 - 25 = 20

65 - 45 = 20

as you can see the common difference between the 3 consecutive numbers 25 , 45 and 65 is a constant (20)

so ,we are in an arithmetic sequence case with :

  • first term 25
  • common difference r = 20

Let’s label the sequence: Un

then

Un = U1 + (n-1)×r

    = 25 + (n-1)×20

    = 20n + 5

for n = 10 → U10 = 20(10) + 5 = 200 + 5 = 205

5 0
4 years ago
A runner runs at 7.6mph for 3 1/2 hours how many miles did he run
posledela
He ran 26 6/10 miles. 7.6x3.5=26.6. I hope this helps!
7 0
4 years ago
Read 2 more answers
Need some help! <br>help giving 10 points ​
steposvetlana [31]

Answer:

The remaining lenghts are x = 20.364\,cm and y = 12.925\,cm.

Step-by-step explanation:

Given that there are two triangles opposite to each other and between two parallel lines, then both are similar, meaning than following relationships exist:

\frac{AC}{CD} = \frac{BC}{CE} = \frac{AB}{DE} (1)

If we know that AC = 11\,cm, CD = 28\,cm, BC = 8\,cm and DE = 32.9\,cm, then the missing lengths are, respectively:

\frac{11\,cm}{28\,cm} = \frac{8\,cm}{x}

x = \frac{(28\,cm)\cdot (8\,cm)}{11\,cm}

x = 20.364\,cm

\frac{11\,cm}{28\,cm} = \frac{y}{32.9\,cm}

y = \frac{(11\,cm)\cdot (32.9\,cm)}{28\,cm}

y = 12.925\,cm

The remaining lenghts are x = 20.364\,cm and y = 12.925\,cm.

5 0
3 years ago
Type A is 2 feet tall and grows at a rate of 17 inches per year. Type B is 10 feet tall and grows at a rate of 5 inches per year
Svetllana [295]

Answer:

Therefore after 3 years the height of these tree will be same.

Step-by-step explanation:

Given that,

Type A is 2 feet tall and grows at a rate of 17 inches.

Type B is 10 feet tall and is growing at a rate of 5 inches.

1 feet = 12 inches,

2 feet= (12×2) inches = 24 inches

5 feet= (12×5) inches = 60 inches

Let after t years, the height of these tree will be same.

After t years, the height of type A is =(24+17t)

After t years, the height of type B is =(60+5t)

According to the problem,

24+17t=60+5t

⇒17t-5t=60-24

⇒12t = 36

⇒t = \frac{36}{12}

⇒t=3

Therefore after 3 years the height of these tree will be same.

7 0
3 years ago
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