He will travel 55km In 2.5 hours at a rate of 22kmph
Answer:
d=117.33 m
Step-by-step explanation:
Initial velocity of planes, u = 0 (because they are at rest)
Acceleration, a = 3.3 m/s²
Final take off speed, v = 88 m/s
We need to find the minimum allowed length for the runway. Let it is d. d will be the distance. It can be calculated using third equation of motion as follows :

Putting all the values, we get :

Hence, the minimum allowed length for the runway is 117.33 m.
Answer:
$32.18
Step-by-step explanation:
It's really just addition. No explanation necessary.
In this section we are going to see how knowledge of some fairly simple graphs can help us graph some more complicated graphs. Collectively the methods we’re going to be looking at in this section are called transformations.
Vertical Shifts
The first transformation we’ll look at is a vertical shift.
N(t) equals 10(number of days times 3) because it says that the numbers triple everyday afterward