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Lyrx [107]
3 years ago
8

LABEL THE TRIANGLE!! PLEASE HELP!!

Mathematics
1 answer:
Anettt [7]3 years ago
8 0

Answer:

Determination of HYP,OPP,ADJ with respect to x.

<u>Opposite</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>right</u><u> </u><u>angle</u><u>:</u><u>Hypotenuse</u><u>:</u><u> </u><u>AC</u>

<u>Opposite</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>given</u><u> </u><u>angle</u><u>:</u><u> </u><u>Opp</u><u>:</u><u>BC</u>

<u>remaining</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>triangle</u><u>:</u><u> </u><u>Adjacent</u><u>:</u><u>AB</u><u>.</u>

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The table below represents a linear relationship.
Ede4ka [16]

Answer:i think it 3

Step-by-step explanation:

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Algebra question (eristhestar please help me)
Svetllana [295]
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7 0
3 years ago
M is the MIDPOINT OF FG. FG = 26 AND GM = (3X - 2)
vova2212 [387]

It is given in the question that

M is the MIDPOINT OF FG.

FG = 26 \  AND \  GM = (3X - 2)

Since M is the midpoint of FG, therefore GM is half of FG. That is

3X-2 = \frac{1}{2} (26)

3X-2 =13&#10;\\&#10;3X = 15&#10;\\&#10;X =5

Therefore

GM = 3(5) -2 = 13

And FM is 13 too .

3 0
3 years ago
1.60. वात्सल्य के अन्तर्गत शिशु स्वरूप के सौंदर्य की अपनी महत्वपूर्ण भूमिका होती है । आपने भी जीवन में
Rus_ich [418]

Answer:

hope it helps

please mark me brainliest

Step-by-step explanation:

वात्सल्य रस का स्थायी भाव है। माता-पिता का अपने पुत्रादि पर जो नैसर्गिक स्नेह होता है, उसे ‘वात्सल्य’ कहते हैं। मैकडुगल आदि मनस्तत्त्वविदों ने वात्सल्य को प्रधान, मौलिक भावों में परिगणित किया है, व्यावहारिक अनुभव भी यह बताता है कि अपत्य-स्नेह दाम्पत्य रस से थोड़ी ही कम प्रभविष्णुतावाला मनोभाव है।

संस्कृत के प्राचीन आचार्यों ने देवादिविषयक रति को केवल ‘भाव’ ठहराया है तथा वात्सल्य को इसी प्रकार की ‘रति’ माना है, जो स्थायी भाव के तुल्य, उनकी दृष्टि में चवर्णीय नहीं है[1]।

सोमेश्वर भक्ति एवं वात्सल्य को ‘रति’ के ही विशेष रूप मानते हैं - ‘स्नेहो भक्तिर्वात्सल्यमिति रतेरेव विशेष:’, लेकिन अपत्य-स्नेह की उत्कटता, आस्वादनीयता, पुरुषार्थोपयोगिता इत्यादि गुणों पर विचार करने से प्रतीत होता है कि वात्सल्य एक स्वतंत्र प्रधान भाव है, जो स्थायी ही समझा जाना चाहिए।

भोज इत्यादि कतिपय आचार्यों ने इसकी सत्ता का प्राधान्य स्वीकार किया है।

विश्वनाथ ने प्रस्फुट चमत्कार के कारण वत्सल रस का स्वतंत्र अस्तित्व निरूपित कर ‘वत्सलता-स्नेह’ [2] को इसका स्थायी भाव स्पष्ट रूप से माना है - ‘स्थायी वत्सलता-स्नेह: पुत्राथालम्बनं मतम्’।[3]

हर्ष, गर्व, आवेग, अनिष्ट की आशंका इत्यादि वात्सल्य के व्यभिचारी भाव हैं।

8 0
3 years ago
A triangle has base 2x+1 and height 6x-3. What value of x would give an area of 240m2?
GREYUIT [131]

Answer:

The values of x which would give an area of 240m² would be:

x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}

Step-by-step explanation:

Given

The base of triangle b = 2x+1

The height of triangle h = 6x-3

The Area of the triangle A = 240 m²

The Area of the triangle has the formula

A = 1/2 × b × h

substituting b = 2x+1, h = 6x-3 and A = 240

240\:=\:\frac{1}{2}\:\left(2x+1\right)\:\times \left(6x-3\right)

480=\left(2x+1\right)\left(6x-3\right)

480=12x^2-3

Subtract 480 from both sides

12x^2-3-480=480-480

12x^2-483=0

3\left(4x^2-161\right)=0

3\left(2x+\sqrt{161}\right)\left(2x-\sqrt{161}\right)=0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

2x+\sqrt{161}=0\quad \mathrm{or}\quad \:2x-\sqrt{161}=0

solving

2x+\sqrt{161}=0

2x=-\sqrt{161}

Divide both sides by 2

\frac{2x}{2}=\frac{-\sqrt{161}}{2}

x=-\frac{\sqrt{161}}{2}

also solving

2x-\sqrt{161}=0

2x=\sqrt{161}

Divide both sides by 2

\frac{2x}{2}=\frac{\sqrt{161}}{2}

x=\frac{\sqrt{161}}{2}

Therefore, the values of x which would give an area of 240m² would be:

x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}

3 0
3 years ago
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