Answer:
<u>______________________________________________________</u>
<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>
For any right angled triangle with one angle α ,
- or
- or
<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>
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<u>______________________________________________________</u>
Now , lets come to the question.
In a right angled triangle , let one angle be α (in place of theta) .
So , lets solve L.H.S.
= R.H.S.
∴ L.H.S. = R.H.S. (Proved)
Answer:
Step-by-step explanation:
2(5-4g) + 3g - 11 = 5(g-3) - 12 - 3g (remove the parantheses)
10 - 8g + 3g - 11 = 5g - 15 - 12 -3g (Calculate and collect like terms)
-1 - 5g = 2g - 27 (move the terms)
-5g -2g = 27 + 1 (collect like terms and calculate)
-7g = -26 (divide both sides)
so G = 26/7
Plugging in (2,-7) into
y=-5x+b, we get that b=3.
Therefore, the equation is y=-5x+3
Answer:
x= (y-5)/2
Step-by-step explanation:
Isolate the x variable.
y= 2x +5
Subtract 5 from both sides.
y-5=2x
Divide both sides by 2.
(y-5)/2= x
Answer: 0.0049 hope this is right