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2 years ago

13

What are the differences between Medicare Part A and Medicare Part B?

2 answers:

alexandr1967 [171]2 years ago

6 0

Medicare Part A is hospital insurance and you get it when you turn 65 automatically. Part B is like a regular insurance policy that you have to pay for, but you aren't eligible to buy it until you are 65. For Medicare Part A to kick in and be the primary during a medical claim, there has to be a qualifying hospitalization (3 overnights), plus a qualifying diagnosis. Part A will carry over and continue coverage in a Skilled Nursing Facility for up to 100 days or for Home Healthcare after hospitalization.

Papessa [141]2 years ago

3 0

Answer:

copy and paste the below if you're on edge it is correct

Step-by-step explanation:

Medicare Part A is hospital insurance and you get it when you turn 65 automatically. Part B is like a regular insurance policy that you have to pay for, but you aren't eligible to buy it until you are 65. For Medicare Part A to kick in and be the primary during a medical claim, there has to be a qualifying hospitalization (3 overnights), plus a qualifying diagnosis. Part A will carry over and continue coverage in a Skilled Nursing Facility for up to 100 days or for Home Healthcare after hospitalization.

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At a time denoted as t=0, a student carrying a new flu virus comes back to an isolated campus that has a fixed number of 1000 pe

Varvara68 [4.7K]

Answer:

$\dfrac{dx(t)}{dt} = kx(t)[1000-x(t)],$ x(0)=0$

Step-by-step explanation:

Total Number of People on Campus =1000

Let the number of people who have contracted the flu =x(t)

Therefore, the number of people who have not contracted the flu =1000-x(t)

Since the rate at which the disease spreads is proportional to the number of interactions between the people who have the flu and the number of people who have not yet been exposed to it.

$\dfrac{dx(t)}{dt} \propto x(t)[1000-x(t)]$

Introducing the proportional constant k, we obtain:

$\dfrac{dx(t)}{dt} = kx(t)[1000-x(t)]$

At t=0, there was no infected on the campus, therefore the initial condition is given:

$x(0)=0$

Therefore, a differential equation for the number of people x(t) who have contracted the flu is:

$\dfrac{dx(t)}{dt} = kx(t)[1000-x(t)],$ x(0)=0$

6 0

2 years ago

Evaluate 9 – b when b = 8 what’s <br> the answer

skad [1K]

Answer:

1

Step-by-step explanation:

9-b is the same as 9-8 because b=8. 9-8=1.

7 0

2 years ago

Jason and Jill or two students in mr. White's math class. On the last 5 quizzes Jason scored an 80 90 95 85 and 70. Jill scored

Mrac [35]

Jason's scores : 80 90 95 85 70 and

Jill's score : 70 75 90 100 95.

Mean of Jason's scores = $\frac{80 + 90 + 95 + 85 + 70}{5}=\frac{420}{5}=84.$

Mean of Jill's scores = $\frac{70+75+90+100+95}{5}=\frac{430}{5}=86$

Now, in order to find the mean absolute deviation, need to find the difference of each score from means.

<u>Mean absolute deviation for Jason's scores.</u>

|84-80| = 4

|84-90| = 6

|84-95| = 9

|84-85| = 1

|84-70|= 14

$\frac{4+6+9+1+14}{5}=\frac{34}{5}=6.8$

<u>Mean absolute deviation for Jill's scores</u>

|86-70| = 16

|86-75| = 11

|86-90| = 4

|86-100| = 14

|86-95|= 9

$\frac{16+11+4+14+9}{5}=\frac{54}{5}=10.8$

Jill got average quiz score 86 and Jason got 84.

Therefore, Jill got better quiz average.

Also, the mean absolute deviation for Jason scores is less that is 6.8 than 10.8.

Therefore, Jason got more consistent grades.

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3 years ago

1. You have 23 coins, all quarters and dimes, totaling $4.85. How many of each coin do you<br> have?

Ksju [112]

the answer is this...

.25x+.10y=4.85

x+y=25

7 0

2 years ago

PLS PLS PLS PLS HELP ITS EASY111 BRAINLIEST POINTS

shusha [124]

Answer:

I think it's A

Step-by-step explanation:

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2 years ago