Answer:
xy = 1
k = 79
Step-by-step explanation:
Question One
The first and third frames look to me to be the same. I'll treat them that way.
y = x^2 Equate y = x^2 to the result of 2y + 6 = 2x + 6
2y + 6 = 2(x + 3) Remove the brackets
2y + 6 = 2x + 6 Subtract 6 from both sides
2y = 2x Divide by 2
y = x
Now solve these two equations.
so x^2 = x
x > 0
1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is
x(x) = x Divide both sides by x
x = 1
y = x^2 Put x = 1 into x^2
y = 1^2 Solve
y = 1
The second solution is
(1,1)
xy = 1*1
xy = 1
Answer: A
Question Two
square root(k + 2) - x = 0
Subtract x from both sides
sqrt(k + 2) = x Square both sides
k + 2 = x^2 Let x = 9
k + 2 = 9^2 Square 9
k + 2 = 81
k = 81 - 2
k = 79
Rewrite in standard form using (h,k) to find the vertex.
(3,4) is the answer.
Answer:
The company earns $6000 more in July than June.
Step-by-step explanation:
In June your company had a loss of 1,200 after making some changes your company profited 4,800 for the month of July.
Now, we have to calculate the earning of the month of July with respect to the month of June.
The earning in June month was - $1200 and in July was + $4800.
Therefore, the company earns $[4800 - (- 1200)] = $6000 more in July than June. (Answer)
Answer:
The sequence diverges
Step-by-step explanation:
The given sequence is 1, 4, 15, 64, 128, ...
By observation the sequence can be expressed as a sequence of 4 raised to increasing powers of 'x' as follows;
The sequence is 4ˣ, where; x = 0, 1, 2, 3, 4, ..., ∞
Therefore, the values of each subsequent term of the sequent is higher than the term it succeeds, the sequence does not converge to a given limit value and therefore, the sequence diverges.
