All categories

3 years ago

Un rombo tiene un ángulo de 22 grados. Cuanto vale la suma de sus ángulos que no midan 22 grados?

Mathematics

1 answer:

Igoryamba3 years ago

5 0

Answer:

The sum of the angles that do not measure 22 degrees is equal to 316°

Step-by-step explanation:

The question in English is

A rhombus has a 22-degree angle. How much is the sum of its angles that do not measure 22 degrees worth?

we know that

The opposite internal angles of a rhombus are equal and the adjacent internal angles are supplementary

Let

x -----> the measure of an adjacent angle to 22 degrees in the rhombus

x+22°=180°

x=180°-22°=158°

therefore

The sum of the angles that do not measure 22 degrees is equal to

158°+158°=316°

You might be interested in

Help me plz !!!?!?!?!

olganol [36]

I believe the answer is the second one I am in the same class.

5 0

3 years ago

How many digits are there in Hindu- Arabic system

kobusy [5.1K]

10 digits.
0, 1, 2, 3, 4, 5, 6, 7, 8, and 9

5 0

3 years ago

Someone please help for a brainly

ivolga24 [154]

Answer:

it's 3 it's it

Step-by-step explanation:

trust me okay I promise dude I a easy yes yes 3

6 0

3 years ago

Is Y=-3/4x -2 Y=3/4x+1 One solution many solution or no solution

Mama L [17]

I’m not sure what I can do

8 0

3 years ago

At what values of x does f(x) = x^3 - 2x^2 -4x+1 satisfy the mean value theorwm on [0,1]

denis-greek [22]

Answer:

x=1/3

Step-by-step explanation:

A function f is given as

$f(x) = x^3-2x^2-4x+1$ in the interval [0,1]

This function f being an algebraic polynomial is continuous in the interval [0,1] and also f is differntiable in the open interval (0,1)

Hence mean value theorem applies for f in the given interval

$f(1) = 1-2-4+1 = -4\\f(0) = 1$

The value

$\frac{f(1)-f(0)}{1-0} =\frac{-4-1}{1} =-5$

Find derivative for f

$f'(x) = 3x^2-4x-4$

Equate this to -5 to check mean value theorem

$3x^2-4x-4=-5\\3x^2-4x+1=0\\\\(x-1)(3x-1) =0\\x= 1/3 : x = 1$

We find that 1/3 lies inside the interval (0,1)

4 0

3 years ago