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3 years ago

12

What is the equation of the line that passes through

1 answer:

irinina [24]3 years ago

7 0

Solve equation for y.

5x - y = 3

-y = -5x + 3

y = (-5x + 3)/(-1)

y = 5x - 3

The slope for this equation is 5.

The slope of the equation we want is the negative reciprocal of 5.

Let m = slope of equation we want.

m = -1/5

We are given the point (10,4).

Plug both into the point-slope formula.

y - 4 = (-1/5)(x - 10)

y - 4 = (-1/5)x + 2

y = (-1/5)x + 2 + 4

The equation we want is

y = (-1/5)x + 6

Did you follow?

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laiz [17]

It is a function because they are.

3 0

3 years ago

What is 2 1/6 * 1 1/4 equal too

timofeeve [1]

Hmmm idk if you want fractions but, 65/24 or 2 17/24 I think

6 0

3 years ago

What is an equation of the line that passes through the point (-6,7) and is perpendicular to the line

Temka [501]

The equation of line perpendicular to given line through (-6,7) is:

$y=\frac{1}{6}x+8$

Further explanation:

Given equation of line is:

$6x+y=3\\y= -6x+3$

The co-efficient of x is the slope of given line.

Let m1 be the slope of given line

and

m2 be the slope of line perpendicular to given line

Then

$m_1=-6$

Product of slopes of perpendicular lines is -1

$m_1*m_2 = -1\\-6*m_2=-1\\m_2=\frac{-1}{-6}\\m_2=\frac{1}6}$

The equation of new line can be written as:

$y=m_2x+b\\$

Putting m2

$y=\frac{1}{6}x+b$

To find the value of b, we will put (-6,7) in equation

$7=\frac{1}{6}(-6)+b\\7=-1+b\\b=7+1\\b=8$

Putting the values of b and m in general equation

$y=\frac{1}{6}x+8$

Keywords: Slope, Point-slope form, perpendicular lines

Learn more about perpendicular lines at:

#LearnwithBrainly

5 0

3 years ago

15) g(n) = 2n + 5 f(n) = -4n-1 Find g(f(n))

Lisa [10]

Answer:

g[f(n)] = -8n+3

Step-by-step explanation:

Given,

g(n) = 2n + 5 , f(n) = -4n-1

Find g(f(n)),

Solutions,

g[f(n)] = g[-4n-1]

= 2(-4n-1) + 5

= -8n–2+5

g[f(n)] = -8n+3

Final Answer = g[f(n)] = -8n+3.

6 0

3 years ago

Please answer or comment if your good at math and willing to help please

olganol [36]

Answer: Indeed i am

Hope This helps :)

7 0

2 years ago