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Sphinxa [80]
2 years ago
9

What type of triangle is this ?

Mathematics
1 answer:
swat322 years ago
3 0

Answer:

Scalene Triangle

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What do skew lines look like
zhuklara [117]

Answer:

"In three-dimensional geometry, skew lines are two lines that do not intersect and are not parallel. A simple example of a pair of skew lines is the pair of lines through opposite edges of a regular tetrahedron."

Step-by-step explanation:

5 0
3 years ago
What is the X<br> 3x +15 and 2x + 20
Georgia [21]

Answer:

<h2><u><em>x = 5</em></u></h2>

Step-by-step explanation:

What is the X

3x +15 and 2x + 20

assuming that the question is an equation

3x + 15 = 2x + 20

3x - 2x = 20 - 15

x = 5

-----------------

check

3 * 5 + 15 = 2 * 5 + 20

30 = 30

the answer is good

5 0
1 year ago
At 2:00pm a car's speedometer reads 20mph, and at 2:10pm it reads 30mph.
Dmitry [639]

Over this 10-minute interval, the car's average acceleration is

\dfrac{30\,\mathrm{mph}-20\,\mathrm{mph}}{10\,\mathrm{min}}=\dfrac{10\,\mathrm{mph}}{\frac16\,\mathrm h}=60\dfrac{\rm mi}{\mathrm h^2}

The MVT says that at some point during this 10-minute interval, the car must have had an acceleration of 60 mi/h^2.

6 0
3 years ago
Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam
tigry1 [53]

Answer:

P(A) = \frac{30}{100}

P(B) = \frac{77}{100}

P(A\ n\ B) = \frac{22}{100}

P(A\ u\ B) = \frac{85}{100}

Step-by-step explanation:

Given

See attachment for proper format of table

n = 100 --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

Yes = 22 and No = 8

So, we have:

n(A) = Yes + No

n(A) = 22 + 8

n(A) = 30

P(A) is then calculated as:

P(A) = \frac{n(A)}{Sample}

P(A) = \frac{30}{100}

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

(1) = 22    (2) = 25 and (3) = 30

So, we have:

n(B) = (1) + (2) + (3)

n(B) = 22 + 25 + 30

n(B) = 77

P(B) is then calculated as:

P(B) = \frac{n(B)}{Sample}

P(B) = \frac{77}{100}

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

n(A\ n\ B) = 22

The probability is then calculated as:

P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}

P(A\ n\ B) = \frac{22}{100}

Solving (d): P(A u B)

This is calculated as:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)

This gives:

P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}

Take LCM

P(A\ u\ B) = \frac{30+77-22}{100}

P(A\ u\ B) = \frac{85}{100}

8 0
3 years ago
How would the following triangle be classified?
Anna [14]

Answer:

hope this helpful

Step-by-step explanation:

isosceles right

because A light ray incident at 90° at the first face emerges at the same angle. The diagram shows five isosceles right-angled prisms. A light ray incident at 90° at the first face emerges at the same angle with the normal from the last face.

8 0
2 years ago
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