Mike tosses 70%
Ike tosses 67%
Both tosses 50%
<span>Which of the following is closest to the probability that Ike's proportion is ringers is higher than Mike's for those tosses?
</span>
P(m) = 70/100
P(i) = 67/100
P(b) = 50/100
= P(b) * P(i)
= 50/100 * 67/100
= 0.335
The correct answer is letter D) 0.3745.
Answer:
$600
Step-by-step explanation:
I = 2000(.15)(2)
I = 600
2,997.99 would be the whole number :)
if you want to see it in a problem.. 2,900 + 90 + 7 + .9 + .09 = 2,997.99