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3 years ago

Who has 4 projects due Friday and hasn't started but you should be

Mathematics

1 answer:

Lina20 [59]3 years ago

4 0

Answer:

Oof not me but thanks for the free points lol

You might be interested in

From 75 pencils to 225 penicls

Masja [62]

Answer:

He gained 150 pencils

Step-by-step explanation:

So this person had 75 pencils and now has 225?

If so, this is just a subtraction problem!

Steps:

1. 225-75=150

--Subtract how many pencils he had from how many he has now to see how much he gained

This person gained 150 pencils.

Hope this helped!! :)

3 0

3 years ago

the number of women at a training workshop was two less than three times the number of men if 50 people attended the workshop ho

Anton [14]

Answer: 148

Work: 50 men multiplied by 3 =150
If there is two less women from 3 multiplied by 50 (150) , then 150 - 2 = 148

6 0

2 years ago

what is the common number to be subtracted from each term of the ratio 11:8 to get the new ratio 2:1.?

JulijaS [17]

Answer:

5 should be subtracted from each term

Step-by-step explanation:

$\frac{11-x}{8-x}=\frac{2}{1}$

Cross multiply,

1 * (11 - x) = 2*(8-x)

11 -x = 2*8 - 2*x

11 - x = 16 - 2x

Subtract 11 from both sides,

-x = 16 - 2x - 11

-x = 5 - 2x

Add 2x to both sides

-x +2x = 5 - 2 + 2x

x = 5

7 0

2 years ago

In the straightedge and compass construction of the parallel line below, which of the following reasons can you use to prove tha

Eva8 [605]

Answer:

Step-by-step explanation:

Lines EG and CD are cut by transversal CF.

By construction, ∠FEG=∠FCD. These two angles are corresponding angles.

Since two corresponding angles are congruent, then lines EG and CD are parallel (by converse of the corresponding angles postulate).

Converse of the Corresponding Angles Postulate: If the corresponding angles formed by two lines and a transversal are congruent, then lines are parallel.

3 0

2 years ago

Triangle NMO has vertices at N(−5, 2), M(−2, 1), O(−3 , 3). Determine the vertices of image N′M′O′ if the preimage is reflected

Firdavs [7]

Notice that the reflection is over a line of the form x=constant; in this case, the y-coordinate of the reflected point stays the same while the x-coordinate changes as expressed by the transformation below

$\begin{gathered} y\rightarrow y \\ x\rightarrow2a+x \\ where \\ x=a\rightarrow\text{ vertical line} \end{gathered}$

Hence, in our case

$\Rightarrow(x,y)=(2*-4-x,y)=(-8-x,y)$

Transform points N, M, and O accordingly,

$\begin{gathered} \Rightarrow N^{\prime}=(-8-(-5),2)=(-8+5,2)=(-3,2) \\ \Rightarrow M^{\prime}=(-8-(-2),1)=(-6,1) \\ \Rightarrow O^{\prime}=(-8-(-3),3)=(-5,3) \end{gathered}$ <h2>Therefore, the answer is the first option (top to bottom)</h2>

6 0

10 months ago