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3 years ago

I have a 6 in the tens place and 7 in the ones place .I am greater than 200 but less than 400. what number am I?

Mathematics

2 answers:

babunello [35]3 years ago

5 0

267 or 367 might be it

Alinara [238K]3 years ago

3 0

Either 267 or 367. Is there more info?

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BRAINLIEST Please help ASAP and leave a small explanation :)

Andreas93 [3]

1 and 8 are because they are alternate exterior angles

3 0

3 years ago

I got a screenshot, You got answer

liq [111]

Answer:

A. $V = (pi)(3.25)^2(12)$

Step-by-step explanation:

The formula for the volume of a cylinder is the formula for the area of the circle, times the height of the cylinder. The formula for the volume of a circle is,

$A = (pi)(r)^2$

Multiply that by the height to find the formula for the volume of a cylinder,

$V=(pi)(r)^2(h)$

Where (pi) represents the value (3.1415), (r) represents the radius, and (h) represents the height of the cylinder. Now substitute in the given values, remember, this problem gives the diameter of the cylinder, divide that value by two to find the radius.

$V=(pi)(\frac{6.5}{2})^2(12)\\\\V = (pi)(3.25)^2(12)$

3 0

3 years ago

Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati

Brrunno [24]

Remember that an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.

Lets solve our equation to find out what is the extraneous solution:
 $\sqrt{x-3} =x-5$
$(\sqrt{x-3})^2 =(x-5)^2$
$x-3=x^2-10x+25$
$x^2-11x+28=0$
$(x-4)(x-7)=0$
$x-4=0$ and $x-7=0$
$x=4$ and $x=7$

So, the solutions of our equation are $x=4$ and $x=7$ . Lets replace each solution in our original equation to check if they are valid solutions:
- For $x=7$
$\sqrt{x-3} =x-5$
$\sqrt{7-3} =7-5$
$\sqrt{4} =2$
$2=2$
We can conclude that 7 is a valid solution of the equation.

- For $x=4$
$\sqrt{x-3} =x-5$
$\sqrt{4-3} =4-5$
$\sqrt{1} =1$
$1 \neq 1$
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: D. the extraneous solution is x = 4

7 0

3 years ago

. Solve for x: 2% of x = 17 a 34 b 8.5 c 85 d 850

blsea [12.9K]

Answer:850

Step-by-step explanation:

To find this 2% of x= 17

2/100×x=17

2x/100=17

2x=1700

x=850

4 0

3 years ago

Gender: Grade 9 Grade 10 Grade 11 Grade 12

Karolina [17]

There are 31+42+50+61=184 total females, and 50+61=111 females in grades 11 and 12, so the percentage is 111/184*100=60.33 percent, which can be rounded to 60%.

4 0

4 years ago

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I have a 6 in the tens place and 7 in the ones place .I am greater than 200 but less than 400. what number am I?​

I have a 6 in the tens place and 7 in the ones place .I am greater than 200 but less than 400. what number am I?