So what this is is
many words
assuming year 0 is 2017
so compound first thing till 2020, take out 30000
the remaining is copmpounded til 2022, take out 50000
remaining is compounded for 1 more year and that is equal to 80000
so from 2017 to 2020, that is 5 years
from 2020 to 2022 is 2 years
from 2022 to 2023 is 1 year
work backwards
A=P(r+1)^t
last one
A=80000
P=?
r=0.08
t=1 year
80000=P(1.08)^1
divide both sides by 1.08
I would leave in fraction
20000000/27=P
now that is the remaining after paying 50000, after 2 years of compounding
so
50000+(2000000/27)=P(1.08)^2
solve using math
about
106374=P
now reverse back
5 years
paid 30000
30000+106374=P(1.08)^5
solve using math
92813.526=P
round
$92813.53
put $92813.53 in the fund
Male steps: 55,375
Female steps:62,926
Answer:
-3
Step-by-step explanation:
Short AnswerThere are two numbers
x1 = -0.25 + 0.9682i <<<<
answer 1x2 = - 0.25 - 0.9582i <<<<
answer 2 I take it there are two such numbers.
Let one number = x
Let one number = y
x + y = -0.5
y = - 0.5 - x (1)
xy = 1 (2)
Put equation 1 into equation 2
xy = 1
x(-0.5 - x) = 1
-0.5x - x^2 = 1 Subtract 1 from both sides.
-0.5x - x^2 - 1 = 0 Order these by powers
-x^2 - 0.5x -1 = 0 Multiply though by - 1
x^2 + 0.5x + 1 = 0 Use the quadratic formula to solve this.

a = 1
b = 0.5
c = 1

x = [-0.5 +/- sqrt(0.25 - 4)] / 2
x = [-0.5 +/- sqrt(-3.75)] / 2
x = [-0.25 +/- 0.9682i
x1 = -0.25 + 0.9682 i
x2 = -0.25 - 0.9682 i
These two are conjugates. They will add as x1 + x2 = -0.25 - 0.25 = - 0.50.
The complex parts cancel out. Getting them to multiply to 1 will be a little more difficult. I'll do that under the check.
Check(-0.25 - 0.9682i)(-0.25 + 0.9682i)
Use FOIL
F:-0.25 * -0.25 = 0.0625
O: -0.25*0.9682i
I: +0.25*0.9682i
L: -0.9682i*0.9682i = - 0.9375 i^2 = 0.9375
NoticeThe two middle terms (labled "O" and "I" ) cancel out. They are of opposite signs.
The final result is 0.9375 and 0.0625 add up to 1
Answer:
a) 
b) 5464 inhabitants.
Step-by-step explanation:
The formula used for compound interest becomes very helpful in this case.

Knowing this, we can easily calculate the value for any year, counting from the original 5000.
From this formula, we can derive a specific one that will serve for any value of <em>t</em>.
a)

b) Apply the formula:

The town will have 5464 inhabitants.