I believe the answer is 64
First break it off into 2 rectangles on is 4 width and 10 length other is 8 length and 10 width. Then multiple to find area 10•4=40 8•3=24 then add 40+24= 64
Do u have an attachment?? :)
The perimeter p of the rectangle with length l and width w is:
p = 2l + 2w
that is, two times its length and two times its width, lets solve for the width w and substitute known data:
<span>p = 2l + 2w
</span>2w = p - 2l
w = (<span>p - 2l</span>)/2
w = (56 - (2*12))/2
w = (56 - 24)/2
w = 32/2
w = 16
therefore the width of the rectangle is 16 in
Answer:
Do you mean y? if you did it should be 1/6 or 1.666666 repeating.
Step-by-step explanation:
I needed the 6y to = 1 so I did the inverse of it by and got 1 so y should = 1/6
Answer 1:16 is the answer
