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padilas [110]
3 years ago
12

What is the value of m? 3m+2-1/4m=1/2(m-5)

Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
6 0

Answer:

m=-2

hope this helped:)

Brainliest?

sertanlavr [38]3 years ago
5 0

Answer:

M=-2

Step-by-step explanation:

3m+2−1/4m=1/2(m−5)

Step 1: Simplify both sides of the equation.

3m+2−1/4m=1/2(m−5)

3m+2+−1/4m=(1/2)(m)+(1/2)(−5)(Distribute)

3m+2+−1/4m=1/2m+−5/2

(3m+−1/4m)+(2)=1/2m+−5/2

(Combine Like Terms)

11/4m+2=1/2m+−5/2

11/4m+2=1/2m+−5/2

Step 2: Subtract 1/2m from both sides.

11/4m+2−1/2m=1/2m+-5/2−1/2m

9/4m+2=−5/2

Step 3: Subtract 2 from both sides.

9/4m+2−2=−5/2−2

9/4m=−9/2

Step 4: Multiply both sides by 4/9.

(4/9)*(9/4m)=(4/9)*(−9/2)

m=−2

Answer:

m=−2

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a student walks 50m on a bearing 0.25 degrees and then 200m due east how far is she from her starting point.​
Inessa05 [86]

Answer:

Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.

** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.

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Now let's begin.

We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:

A_x=50cos(89.75) so

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B_x=200cos(0) so

B_x=200 and we need to add those results together. Due to the rules for adding significant digits properly, the answer is

C_x=200 (and remember I am counting that as 3 sig fig's even though it's only 1).

Now for the y components:

A_y=50sin(89.75) so

A_y=50 (which I'm counting as 2 sig fig's)

B_y=200sin(0) so

B_y=0 and we need to add those results together.

C_y=50

Now for the resultant magnitude:

C_{mag}=\sqrt{(200)^2+(50)^2}  and that gives us a final magnitude of

C_{mag}=206 m

Now for the angle:

Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so

tan^{-1}(\frac{50}{200})=14

The girl is 206 meters from her starting point at an angle of 14 degrees

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Answer:

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Step-by-step explanation:

If in 1 minute he can type 30 words , then in 9.5 min he can type  30 x 9.5 = 285.0 = 285

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