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Serhud [2]
2 years ago
11

(7+i)-(6-4i) whats this answer as a complex number in standard form.

Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
5 0

Remove parenthesis, rearrange, and combine like terms.

7+i-6+4i

1i+4i+7-6

5i+1

---

hope it helps

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4 (k - 6) = 6 (-4 - 5k)<br> a) 10<br> b) 0<br> c) -2<br> d) 8
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Step-by-step explanation:

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step 3. 4k - 24 = -24 - 30k

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Sever21 [200]
<h3>Answer: Choice D</h3>

Divide both sides of the first equation by 7, then add the result to the second equation

=======================================================

Explanation:

We can multiply both sides of an equation by the same number and the equation will be equivalent to the original.

For example, if we had  x = 5, then we could get 2x = 10 after multiplying both sides by 2. The reason they are equivalent equations is because the same x value is the solution for both equations.

We can also divide both sides of an equation by the same number and the two equations would be equivalent. We can go from 2x = 10 back to x = 5 when we divide both sides by 2.

----------

If we divide both sides of 7x - 21y = 14 by 7, then we end up with x - 3y = 2. Simply divide each term (7x,  -21y, and 14) by 7.

Because 7x-21y=14 and x-3y=2 are equivalent, this means we can replace the "7x-21y=14" with "x-3y=2"

--------

The new system would be

x-3y = 2

2x+3y = 11

From here you add straight down. Doing so will have the y terms add to -3y+3y = 0y = 0. After this point the y terms are eliminated and you can solve for x just like with any other equation of one variable.

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