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3 years ago

3n to the 2nd power+2

Mathematics

1 answer:

steposvetlana [31]3 years ago

3 0

Answer:

11n

Step-by-step explanation:

We don't know the value of N, so we leave that the same.

3 to the second power, (3x3)= 9.

We have to add 2 to 9, so 9+2=11

Add your n to the end, and your answer is 11n.

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How can you use the multiplication property of equality to rewrite the equation 0.6x+4.8=7.2 so that the numbers in the problem

Mars2501 [29]

We are given the equation:

0.6 x + 4.8 = 7.2

In this case, the multiplication property of equality states that whatever is multiplied on one side should also be multiplied on the other side. Now we need to find the number that will make everything a whole number, in this case 5. Multiply everything by 5:

5 * (0.6 x + 4.8 = 7.2)

3 x + 24 = 36

However we can see that we can still further simplify the equation by multiplying everything by 1/3:

(1/3) * (3 x + 24 = 36)

x + 8 = 12

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3 years ago

At Haines Elementary, 30% of the 120 teachers were male. The following school year, several new teachers were hired. The number

zhannawk [14.2K]

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3 years ago

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3 years ago

Read 2 more answers

A population of rabbits triples every month.the population starts with two rabbits.how many rabbits are there after 3 month's

Tresset [83]

The answer would be 54. Because you start with 2.
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7 0

3 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

8 0

3 years ago