Qual é a frequência de cada gênero de leitura citados?

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

6 0

Answer:

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Can someone please help me

AysviL [449]

Answer:

20 ft

Step-by-step explanation:

Keep in mind that, both ratios are the same, let the length of the shadow be x, then you can make an equation that 30/ 40 = 15 / x, then 30x = 15 * 40 = 600, so x = 20.

4 0

3 years ago

Jerome solves the inequality y–2 ⩽ 9 in one step, writing y ⩽ 11 as the solution. What property best justifies the step he used

DedPeter [7]

The answer is b because he added 2

8 0

3 years ago

Which trigonometric ratios are correct for triangle ABC? Check all that apply

sergij07 [2.7K]

Consider an angle M with measure m≠90°, in a right triangle.

Let

OPP denote the length of the side opposite to M,
ADJ denote the length of the side adjacent to M, and
HYP denote the hypotenuse.

then:

Sin(M) = OPP/HYP
Cos(M)= ADJ/HYPP
Tan(M)=OPP/ADJ

Back to our problem,

using the Pythagorean we can find the length of AB:

$|AB|^2+|AC|^2=|BC|^2\\\\|AB|^2+9^2=18^2\\\\|AB|^2=18^2-9^2\\\\|AB|^2=(18-9)(18+9)=9 \cdot 27=9 \cdot 9 \cdot3\\\\|AB|=9 \sqrt{3} 
$

$Sin(C)= \frac{OPP}{HYP}=\frac{9 \sqrt{3} }{18}= \frac{ \sqrt{3} }{2}$
$Cos(B)= \frac{ADJ}{HYP}= \frac{9 \sqrt{3}}{18}= \frac{ \sqrt{3}}{2}$
$Tan(C)= \frac{OPP}{ADJ}= \frac{9 \sqrt{3} }{9}= \sqrt{3}$
$Sin(B)= \frac{OPP}{HYP}= \frac{9}{18}= \frac{1}{2}$
$Tan(B)= \frac{OPP}{ADJ}= \frac{9}{9 \sqrt{3}}= \frac{1}{ \sqrt{3} }= \frac{ \sqrt{3}}{3}$

Answer: 1, 3, 4

5 0

3 years ago

Pls help me, I really need help

jeka94

Answer:

i think it is b

Step-by-step explanation:

7 0

3 years ago

Una escuela secundaria tiene 840 alumnos inscritos, de esta cantidad al 25% les asignaron una beca. ¿Cuántos alumnos fueron beca

Ratling [72]

Answer: C) 210

Step-by-step explanation:

Multiplica 0.25 y 840 para encontrar el 25% de 840

6 0

3 years ago

Qual é a frequência de cada gênero de leitura citados?​

Qual é a frequência de cada gênero de leitura citados?