The angles of a quadrilateral add to 360, so we can solve for x by adding the 4 angle measures together and setting it equal to 360:
90 + 140 + (x - 10) + (x - 20) = 360
Combine like terms:
230 + 2x - 30 = 360
200 + 2x = 360
200 - (200) + 2x = 360 - (200)
2x = 160
Divide both sides by 2:
2x/(2) = 160/(2)
x = 80
Answer:
One dollar
Step-by-step explanation:
So you divide 8.70 by 87 to get 0.10. So then you multiply 0.10 by 10 to get a dollar
Answer is 56 because on his 3rd exam he got 57 word per minute, since he got 57 he can take out 7 of those words and he would still have 50. Remember the extra 7 words we have. Then you would calculate how many more words he needs to get to fifty on his other exams which are 4,6,and 3. Add these 3 and you get 13. Remember we still have that extra 7. We pick 56 with the extra 7 it would be 63. You can take out 13 words to fill in the other exams and u would still be left with 50.
Therefor your answer is 56.
Answer:
y = 2x − 1
Step-by-step explanation:
By eliminating the parameter, first solve for t:
x = 4 + ln(t)
x − 4 = ln(t)
e^(x − 4) = t
Substitute:
y = t² + 6
y = (e^(x − 4))² + 6
y = e^(2x − 8) + 6
Taking derivative using chain rule:
dy/dx = e^(2x − 8) (2)
dy/dx = 2 e^(2x − 8)
Evaluating at x = 4:
dy/dx = 2 e^(8 − 8)
dy/dx = 2
Writing equation of line using point-slope form:
y − 7 = 2 (x − 4)
y = 2x − 1
Now, without eliminating the parameter, take derivative with respect to t:
x = 4 + ln(t)
dx/dt = 1/t
y = t² + 6
dy/dt = 2t
Finding dy/dx:
dy/dx = (dy/dt) / (dx/dt)
dy/dx = (2t) / (1/t)
dy/dx = 2t²
At the point (4, 7), t = 1. Evaluating the derivative:
dy/dx = 2(1)²
dy/dx = 2
Writing equation of line using point-slope form:
y − 7 = 2 (x − 4)
y = 2x − 1
