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irga5000 [103]
3 years ago
6

The equation y minus 3 = negative 2 (x + 5) is written in point-slope form. What is the y-intercept of the line?

Mathematics
2 answers:
djverab [1.8K]3 years ago
8 0

Answer:

y=-7

Step-by-step explanation:

y-3=-2(x+5)

distribute the -2 into the ( )

y -3= -2x -10

cancel to -2x

y- 3 = -2(0) -10

y-3 = -10

  +3   +3

y= -7

Hope this helps!!

Amanda [17]3 years ago
4 0

Answer:

the y intercept is -7

Step-by-step explanation:

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What is the solution to the proportion?<br> 5/x = 2/16
mixas84 [53]

Answer:

I believe the answer is X=40

Step-by-step explanation:

cross multiply 5*16 = X * 2

Multiply 5*16

80= X*2

Add '-2x' to each side of the equation

80 + -2x = 2x + -2x

Combine like terms

80 + -2x = 0

Add '-80' to each side of the equation.

80 + -80 + -2x = 0 + -80

Combine like terms: 80 + -80 = 0

0 + -2x = 0 + -80

-2x = 0 + -80

Combine like terms: 0 + -80 = -80

-2x = -80

Divide each side by '-2'.

x = 40

Simplifying

x = 40

Hope this helped :)

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Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex
bagirrra123 [75]

Answer:

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

\hat p=0.021 estimated proportion of interest

p_o=0.012 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:  

Null hypothesis:p \leq 0.012  

Alternative hypothesis:p > 0.012  

When we conduct a proportion test we need to use the z statisitic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>3.363)=0.00039  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0
3 years ago
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