The billiard balls without replacement.
Let's say there are 10 billiard balls 5 red and 5 blue.
If you pick a blue ball on the first pick you had a 5/10 chance
Now your chances of getting a red are only 5/9.
What happened on the first pick affects what happens on the second (making it dependent)
In this question, you are only able to cancel out the (x + 5). The others are unable to be cancelled.
Answer:
The Sample space DOES change, each event within the sample space DOES NOT change, The probability of each event does change. The new probability of drawing a red marble is p(R)= 1/
Step-by-step explanation:
I dont know how many red marbles are in the Jar before so I cant do that for you.
It would be greater, because 1 foot is equal to 12 inches. 8 times 12 is 96. Then 96 plus 6 inches in 102. So it would be greater.
Answer:
Twenty two over nine.
Step-by-step explanation:
The bar over the 4 means that 4 is recurring .44444......... It goes on with out bounds and is equal to 4/9.
So 2.4 = 2 4/9
= 22/9.
