PLEASE HELP ME! SOMEONE!

Mathematics

1 answer:

stepan [7]4 years ago

3 0

The basic idea is that you draw perpendicular bisectors of two of the sides, then use their point of intersection as the center of the circle.

To construct the perpendicular bisectors, set your compass to a width that is greater than half the length of the longest side. In the attached picture, we noticed that DE is more than half the length of EF, so we simply used the length DE for the compass setting. Draw circles at each of the vertices with this radius.

There will be points where the circles intersect that are equidistant above and below the center of each side. Mark two pairs of these points. In the diagram, we have labelled them A, B, C, G. Draw the perpendicular bisectors of the triangle sides through these points. The points and lines are colored green in the figure.

The point of intersection of the bisectors is the center of the circle you want. In the figure, we have marked it H and colored it red. Reset your compass to have a radius of HD (or HE or HF—they should all be the same) and draw the circle at H through D, E, and F. It is red in the diagram. That is the circle the problem is asking for.

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A toy baseball bat comes with 3 plastic balls. The balls are in a box that is a rectangular solid. The box is just big enough to

vodomira [7]

Answer:

31.4 in³

Step-by-step explanation:

The box is just big enough to hold the 3 balls, so it must have a length 6 times the radius of each ball, a width 2 times the radius, and a height 2 times the radius.

The volume of the box is:

V = (6r)(2r)(2r)

V = 24r³

The volume of the 3 balls is:

V = 3 (4/3 π r³)

V = 4πr³

So the volume of the air is:

V = 24r³ − 4πr³

V = (24 − 4π) r³

Since r = 1.4 inches:

V = (24 − 4π) (1.4 in)³

V ≈ 31.4 in³