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AlexFokin [52]
3 years ago
15

Solve the equation (3x/2) (3x/4) - 3 6^​

Mathematics
1 answer:
Leya [2.2K]3 years ago
8 0

Answer:

x=25.45

Step-by-step explanation:

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Determine the axis of symmetry and the vertex of the given function. y = 2x2 − 12x + 21 Axis of symmetry: x = Vertex: ( , )
Varvara68 [4.7K]
The vertex is (3,3) and the axis is 3
5 0
4 years ago
Read 2 more answers
Divide.<br> (4x4 - 4x2 – x-3) = (2x2 – 3)
inn [45]

Given:

Division problem:

(4x^4-4x^2-x-3)\div (2x^2-3)

To find:

The solution for the given division problem.

Solution:

We have,

(4x^4-4x^2-x-3)\div (2x^2-3)

Here, 4x^4-4x^2-x-3 is the dividend and (2x^2-3) is divisor.

Using the long division method we get

\underline{2x^2-3}|\overline{4x^4-4x^2-x-3}|\underline{2x^2+1}

            \underline{4x^4-6x^2}

                      2x^2-x-3                      (After subtraction)

                      \underline{2x^2\quad \quad  -3}

                          \underline{\quad -x\quad}                        (After subtraction)

Now,

\dfrac{4x^4-4x^2-x-3}{2x^2-3}=2x^2+1-\dfrac{x}{2x^2-3}

Therefore, the required solution is 2x^2+1-\dfrac{x}{2x^2-3}.

5 0
3 years ago
Bennett has been practicing the cello for an hour each day. 3/4of the hour, he spends practicing musical pieces in preparation f
mina [271]

Answer:

Orchestral\ Time = \frac{3}{10}\ hour

Step-by-step explanation:

Given

Time = 1\ hour

Musical\ Pieces = \frac{3}{4}\ hour

Practicing\ Sales = \frac{1}{4}\ hour

Orchestral = \frac{2}{5} of music practice time

Required

Determine time spent on orchestral pieces

From the given parameters, we have:

Orchestral = \frac{2}{5} of music practice time

Substitute \frac{3}{4}\ hour for music practice time.

So, we have:

Orchestral\ Time = \frac{2}{5} * \frac{3}{4}\ hour

Orchestral\ Time = \frac{1}{5} * \frac{3}{2}\ hour

Orchestral\ Time = \frac{3}{10}\ hour

7 0
3 years ago
I need the answer to all of them if somebody could give me the answer it would be nice to all of thme
kogti [31]
The third one is r=-10 (don't forget the negative!)
The fourth one is p=-3 (again, watch for the negative)
((I can't get the fifth one, sorry. You might want to repost another question with just that one))
The sixth one is w=35.


Hope this helped a little bit! Sorry I couldn't help with all of them .-. Good luck though!
3 0
3 years ago
if an area can be washed at a rate of 4,900 cm2/ minute, how many square inches can be washed per hour?
Olenka [21]

Answer : 4.5 × 10⁴ square inches can be washed per hour.

Step-by-step explanation :

As we are given that an area can be washed at a rate of 4,900 cm²/min. Now we have to determine the square inches can be washed per hour.

Given conversions are:

1 cm = 0.39 in    and    1 hr = 60 min

As, 1 cm² = (0.39)² in²    and    1 min = 1/60 hr

So, 1cm^2/min=(0.39)^2\times 60in^2/hr

1cm^2/min=9.126in^2/hr

Now we have to determine the square inches can be washed per hour.

As, 1cm^2/min=9.126in^2/hr

So, 4900cm^2/min=\frac{4900cm^2/min}{1cm^2/min}\times 9.126in^2/hr=44717.4in^2/hr=4.5\times 10^4in^2/hr

Therefore, 4.5 × 10⁴ square inches can be washed per hour.

4 0
3 years ago
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