Answer:
The augmented matrix for the system of equations is ![\left[\begin{array}{cccc}0&2&-3&1\\7&0&5&8\\4&1&-3&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D0%262%26-3%261%5C%5C7%260%265%268%5C%5C4%261%26-3%266%5Cend%7Barray%7D%5Cright%5D)
.
Step-by-step explanation:
This system consists in three equations with three variables (
, 
, 
).The augmented matrix of a system of equations is formed by the coefficients and constants of the system of linear equations. In this case, we conclude that the system of equations has the following matrix:
The augmented matrix for the system of equations is .
Answer:
The prices at which manager predict that at least 55 hats will be sold would be would be of $38
Step-by-step explanation:
According to the given data we the following:
Number of hats sold at $18=115
The manager predicts at 3 less will sold for every rise in 1 $ for at least 55 hats.
Therefore, reduction in number=115 hats-55 hats=60
So, increase in price=reduction in number/number of hats manager predicts that will be sold for every $1 increase in price
increase in price=60/3=$20
Therefore, prices at which manager predict that at least 55 hats will be sold would be=$18+$20=$38
The prices at which manager predict that at least 55 hats will be sold would be would be of $38
Yo sup??
m3 and m6 for a supplementary pair therefore
m3+m6=180
122+m6=180
m6=58
Hope this helps
Answer:
Adult=58
Step-by-step explanation:
c=child, a=adult
6.4c+9.7a=1145 equation 1
c+a=149 equation 2
a=149-c modified equation 2 to isolate a
6.4c+9.7(149-c)=1145 substitute value of a from equation 1 into equation 2
6.4c+1445.3-9.7c=1145
-3.3c=-300.3
c=91
solve for a
c+a=149
91+a=149
a=58
Check answer:
6.4c+9.7a=1145
6.4(91)+9.7(58)=1145
582.40+562.60=1145
1145=1145
Answer:
what
Step-by-step explanation:
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