C 12 minutes is the correct answer. Hope this helps :)
the radius of the distance between the middle point of the circle and the outside, we have the diameter which is 6 so the <u>radius will be 3</u>
slant height is
![\sqrt{r^2+h^2}](https://tex.z-dn.net/?f=%5Csqrt%7Br%5E2%2Bh%5E2%7D)
h is 4.7 and r is 3
![\sqrt{3^2+4.71^2} \\5.58427](https://tex.z-dn.net/?f=%5Csqrt%7B3%5E2%2B4.71%5E2%7D%20%5C%5C5.58427)
<u>slant height is 5.58427</u>
lateral surface area
![\pi r\sqrt{h^2+r^2}](https://tex.z-dn.net/?f=%5Cpi%20r%5Csqrt%7Bh%5E2%2Br%5E2%7D)
![\pi (3)\sqrt{4.71^2+3^2} \\52.63053](https://tex.z-dn.net/?f=%5Cpi%20%283%29%5Csqrt%7B4.71%5E2%2B3%5E2%7D%20%5C%5C52.63053)
<u>lateral surface area is 52.63053</u>
total surface area
![\pi r(r+\sqrt{h^2+r^2})](https://tex.z-dn.net/?f=%5Cpi%20r%28r%2B%5Csqrt%7Bh%5E2%2Br%5E2%7D%29)
![\pi 3(3+\sqrt{4.71^2+3^2})](https://tex.z-dn.net/?f=%5Cpi%203%283%2B%5Csqrt%7B4.71%5E2%2B3%5E2%7D%29)
![80.90486](https://tex.z-dn.net/?f=80.90486)
<u>total surface area is 80.90486</u>
1. statement- quadrilateral ABCD Reason- diagonal AEC
Answer:
Yes
Step-by-step explanation:
Since the angle 240° 240 ° is in the third quadrant, the reference angle formula is Ar=Ac−180°<span> A r = A c </span>- 180 °<span> .</span>