A = P(1+r/12)^12t, where A = amount after two years, P = Initial amount = $1000, r =apr = 4.2% = 0.042, t = period = 2 years
Then,
A = 1000 (1+0.042/12)^12*2 = $1087.47
12.93
Use inverse operations
9.27+3.66=12.93
Answer:
Mean 160
Standard deviation 2.63
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean
and standard deviation
, the sample means with size n of at least 30 can be approximated to a normal distribution with mean
and standard deviation 
In this problem, we have that:

Find the mean and standard deviation of the sampling distribution of sample means with sample size n = 58.
Mean 160
Standard deviation 
Answer: 108
lmk if this is wrong
Step-by-step explanation:
V=1/3bh
V=1/3(1/2bh)(h)
V=1/3(1/2)(9)(6)(12)
(i simplified)
V=(1)(1)(3)(6)(6)
V=108
Answer:

63 Jelly Beans
Step-by-step explanation:
The unknown is the number of jelly beans originally in the bag or x
First he had x jelly beans
The he ate one-third of them

He then ate 16 more jelly beans

This was equal to 37 jelly beans

This is the equation
Now solve for x
Subtract 16 from both sides

Multiply both sides by 3

63 Jelly Beans