Can y’all please solve this

Mathematics

1 answer:

Wittaler [7]2 years ago

8 0

A). The answer is x = -4
Work:
3 - x = 11 + x
3 - x - 3 = 11 + x - 3
-x = x + 8
-x - x = x + 8 - x
-2x = 8
-2x/-2 = 8/-2
Answer: x = -4

B). The answer is x = 6
Work:
2x + 7 = 3x + 1
2x + 7 = 3x + 1 - 7
2x = 3x - 6
2x - 3x = 3x - 6 - 3x
-x = -6
-x/-1 = -6/-1
Answer x = 6

C). Answer: x = 4/3
Work:
8 - 2x = 4 + x
8 - 2x - 8 = 4 + x - 8
-2x = x - 4
-2x - x = x - 4 - x
-3x = -4
-3x/-3 = -4/-3
Answer: x = 4/3

D). Answer: x = 2
Work:
4x + 2 = 2x + 6
4x + 2 - 2 = 2x + 6 - 2
4x = 2x + 4
4x - 2x = 2x + 4 - 2x
2x = 4
2x/2 = 4/2
Answer: x = 2

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<u>Step-by-step explanation:</u>

We have, the graph of f(x)= $2^{x}$ , on replacing f(x) by f(x-3) we get:

$f(x-3)$ = $2^{x-3} = \frac{2^{x}}{2^{3}} = \frac{1}{8} 2^{x} = \frac{1}{8} f(x)$ .Below shown are the images for graph of f(x) and f(x-3). Both are functions are exponential , and so having exponential graph but f(x-3) is compressed by a factor of $\frac{1}{8}$ horizontally . Domain and range of both functions are same i.e. F(x) & f(x-3) domain & range are same , just difference in graph : $f(x-3) = \frac{1}{8} f(x)$ .