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taurus [48]
3 years ago
14

What is true about this graph?

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
5 0

Answer:

The function has a range at y _> -2

Step-by-step explanation:

The y axis is at 2 and the x axis is at 2 but you should only examine the y axis that the graph is originally at.

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A student has 6 nickel 14 dimes and 8 quarter. What is the total number of coins?
S_A_V [24]
There is 28 coins total
7 0
3 years ago
Which choices are common factors of the numerator and denominator of 18/24
Andre45 [30]
6/8, 3/4 hopes this helps
5 0
3 years ago
Find the distance between the two points in simplest radical form.<br> (-5,8) and (-3, 1)
elixir [45]

Given:

The two points are (-5,8) and (-3,1).

To find:

The distance between the given two points in simplest radical form.

Solution:

Distance formula: The distance between two points is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, the distance between (-5,8) and (-3,1) is

d=\sqrt{(-3-(-5))^2+(1-8)^2}

d=\sqrt{(-3+5)^2+(-7)^2}

d=\sqrt{(2)^2+(-7)^2}

d=\sqrt{4+49}

d=\sqrt{53}

Therefore, the distance between two points (-5,8) and (-3,1) is \sqrt{53} units.

3 0
3 years ago
Hey! Can someone check my answers?
Andrew [12]
The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}
Since x^{a}* x^{b}  =x^{a+b}, then x^{9}= x^{3}* x^{6}

Back to our expression:
4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+  5y ^{6}*1=5 y^{6} (4y ^{3} +1)
The greatest common factor is thus 5 y^{6}


Q2. The answer is <span>D. 12xy^2
</span>
12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}
We will use the rule  x^{a}* x^{b} =x^{a+b} to factorise the exponents:
12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)
The greatest common factor is thus 12xy^{2}
3 0
4 years ago
Find the probability of spinning an even number AND rolling an odd number.
Agata [3.3K]
You have a 1/2 chance of spinning an even number on the spinner, and a 1/2 chance of rolling an odd number on the die, 1/2 times 1/2 give you a 1/4 chance of doing both of those tasks.
3 0
3 years ago
Read 2 more answers
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