Answer: The angle equals 45
∘ and the supplement is 135
∘
Explanation:
Since the supplement is three times the angle, we can say s = 3
a
Since we know the supplement is
180
−
a
, we can plug that in.
180 - a = 3a
180 =
4
a (add a to both sides)
45 = a (divide both sides by 4)
Since we know the angle now, all we have to do is multiply it times 3 to find the supplement.
45 × 3 = 135
In a triangular prism, B usually stand for the triangular base of the prism. It is the area of the triangle.
Area of a right triangle = ab/2
a = long leg ; b = short leg
Given measures are:
a = 4 yd ; b = 3 yd
A = (4 yd * 3 yd)/2 = 12 yd² / 2 = 6 yd² is the value of B.
the hypotenuse is 5 yd but it is not needed to get the area of the right triangle base. 7 yd is the measure of the height of the triangular prism.
Answer:
Step-by-step explanation:
I'm unsure why my answer was deleted, randomly deleted a thoroughly explained answer.
20% is 20/100, 1/5, or 0.2
The number will decrease by a factor of 5.
Answer:
it is D because it is asking for the opposite of -4 so it would be the tick mark on -4 and 4
Step-by-step explanation:
Answer:
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
This is 1 subtracted by the pvalue of Z when X = 9.08. So



has a pvalue of 0.7823
1 - 0.7823 = 0.2177
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.