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Degger [83]
3 years ago
11

Give me facts on johnson the boxer

Computers and Technology
2 answers:
Zarrin [17]3 years ago
6 0

Answer:

ack Johnson, byname of John Arthur Johnson, (born March 31, 1878, Galveston, Texas, U.S.—died June 10, 1946, Raleigh, N.C.), American boxer who was the first African American to become heavyweight champion. He is considered by many boxing observers to be one of the greatest heavyweights of all time.

Explanation:

Alja [10]3 years ago
6 0

Answer:

Galveston hurricane. Johnson was born in 1878 in Galveston, Texas, and lived there until adulthood. ...

The greatest defensive heavyweight boxer of all time. ...

The first vicious knockout in boxing history.

Explanation:

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Why should the government create money it doesn’t have?
murzikaleks [220]

Answer:

to increase economy of the country

Explanation:

if the government does so the people will be able to access the money this increasing government revenue. This increasing the economy

8 0
3 years ago
Read 2 more answers
a) (20 points) Define the method inDogish recursively such that it returns true if the word is in dog-ish and false if it is not
tia_tia [17]

Answer:

/ Main.java

class Main {

     public static void main(String[] args) {

           //System.out.println(inDogish("aplderogad"));

           //System.out.println(inXish("aplderogad", "dog"));

     }

     // returns true if the word is in dog-ish

     // returns false if word is not in dog-ish

     public static boolean inDogish(String word) {

           /**

           * Note: we can use the inXish() method to complete this method in a

           * single line if you want. just write 'return inXish(word,"dog");' and

           * you are done.

           */

           // if word is null or empty, returning false

           if (word == null || word.length() == 0) {

                 return false;

           }

           // converting word to lower case

           word = word.toLowerCase();

           // if 'd' does not exist on the word, returning false

           if (!dogishHelper(word, 'd')) {

                 return false;

           }

           // removing the characters upto first 'd' in word

           word = word.substring(word.indexOf('d') + 1);

           // if 'o' does not exist on the word, returning false

           if (!dogishHelper(word, 'o')) {

                 return false;

           }

           // removing the characters upto first 'o' in word

           word = word.substring(word.indexOf('o') + 1);

           // if 'g' does not exist on the word, returning false, otherwise

           // returning true

           if (!dogishHelper(word, 'g')) {

                 return false;

           } else {

                 return true;

           }

     }

     // necessary to implement inDogish recursively.

     // returns true if letter is in word, else not.

     public static boolean dogishHelper(String word, char letter) {

           // if word is empty, returning -1

           if (word == null || word.length() == 0) {

                 return false;

           }

           // if first character in word is letter, returning 0

           if (word.charAt(0) == letter) {

                 return true;

           }

           return dogishHelper(word.substring(1), letter);

     }

     // the best thing about the above helper method is that we can use it in

     // inXish method also

     // a generalized version of the inDogish method

     public static boolean inXish(String word, String x) {

           // if x is empty, returning true (base case, which means all the letters

           // in x are in word in that order)

           if (x.length() == 0) {

                 return true;

           }

           // getting first character of x

           char first = x.charAt(0);

           // if first character does not exist on the word, returning false

           if (!dogishHelper(word, first)) {

                 return false;

           }

           // calling and returning inXish recursively, passing the word after

           // removing characters upto first occurrance of char first, and x after

           // removing first character from it

           return inXish(word.substring(word.indexOf(first) + 1), x.substring(1));

     }

}

Explanation:

7 0
4 years ago
If you're driving a car and know there's a motorcyclist around you, you should______. A. Not change your driving B. Check your b
Sedaia [141]

b check your blind spots frequently i guess not sure

5 0
3 years ago
What is the output produced from the following statements? System.out.println("\"Quotes\""); System.out.println("Slashes \\//");
jekas [21]

Answer:

"Quotes"

Slashes \//

How '"confounding' "\" it is!

Explanation:

The question above is testing your knowledge of  the "\" escape sequence, This escape sequence is used to introduce special formatting to the output of the System.out.print function in Java.

It can be used to introduce a new line \n

It can also be used to introduce a tab indentation \t

As in the question above it is used to introduce double quotes "" in this case \"

Also as we see the question above it can still be used to place backlashes to an output in this case we use two backlashes \\. The first is the escape sequence, the second \ gets printed out.

3 0
3 years ago
What is stored in str after the following code executes?
uranmaximum [27]

Answer:

"CoCoComputer Science"

Explanation:

First let's understand how the loop works, then we'll see what it does.

The variable i is initialized to value 0.  Then inside the loop, it's incremented by 2 in each loop passage, while i < 8, so the loop will be processed with the following values of i: 0, 2, 4 and 6.  It will run a total of 4 times.

Let's examine the actions done during the FIRST loop:

(str equals "Computer Science", so indexOf('m') = 2, i = 0)

- if the index of 'm' within the string is < i  (index = 2, i = 0, FALSE)

does nothing

increases value of i by 2 (now i = 2)

Let's examine the actions done during the SECOND loop:

(str equals "Computer Science", so indexOf('m') = 2, i = 2)

- if the index of 'm' within the string is < i  (index = 2, i = 2,  FALSE)

does nothing

increases value of i by 2 (now i = 4)

Let's examine the actions done during the THIRD loop:

(str equals "Computer Science", so indexOf('m') = 2, i = 4)

- if the index of 'm' within the string is < i  ( index = 2,  i = 4, TRUE)

then str becomes "CoComputer Science"

increases value of i by 2 (now i = 6)

Let's examine the actions done during the FOURTH loop:

(str equals "CoComputer Science", so indexOf('m') = 4, i = 6)

- if the index of 'm' within the string is < i  (index = 4,  i = 6, TRUE)

then str becomes "CoCoComputer Science"

increases value of i by 2 (now i=8)

Loop ends because i = 8 (i < 8 becomes false)

6 0
3 years ago
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