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Soloha48 [4]
3 years ago
5

What is the length of the unknown side?

Mathematics
2 answers:
Ulleksa [173]3 years ago
5 0

Answer:

by Pythagoras theram

unknown side is 100

pogonyaev3 years ago
3 0

Answer:

10

Step-by-step explanation:

pythagorean theorem

8^2+6^2=c^2

64+36=c^2

100=c^2

square root both sides

10 = c

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Anne-marienhas saved 9 dollars for a new coat that is 1/6 as much money as she needs how much does the coat cost
Tatiana [17]

Answer:

Cost of the coat = $54

Step-by-step explanation:

Given:

She saved = $ 9

To Find:

Cost of the coat = ?

Solution:

Let the price of coat be x

She saved $9

and according to given condition it is 1/6 of the total money she needs for buying coat

by this we have

\frac{1}{6}*x = 9

Multiplying both sides by 6

\frac{1}{6}*x*6 = 9*6

it becomes

x = 9*6

x = $54

As x is the amount she needs

so

Cost of the coat = $54


7 0
3 years ago
18÷1,322 find the estimate
12345 [234]

the answer is .0136157


6 0
3 years ago
8p+5=-6p+1 what's the answer to this equation?​
Olin [163]

Answer:

-2/7

Step-by-step explanation:

8 0
3 years ago
marcos had 1 1/3 gallons of punch left over. He poured all of it into several containers for family members to take home. use fr
kramer
Hi there, 1 1/3 gallons of punch as a improper fraction is 4/3, 4/3=16/12. Therefore, the answer is 5/16, 4/16, and 7/16.
4 0
3 years ago
Read 2 more answers
What percentage of the semi circle is shaded? <br>​
mezya [45]

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%

r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\% (1)

Where:

  • A_{h} - Area of the half cross, in square centimeters.
  • A_{s} - Area of the semicircle, in square centimeters.
  • r - Percentage of the shaded section of the semicircle.

And the percentage of the shaded section is:

r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100

r \approx 23.606\,\%

The percentage of the semicircle shaded section is approximately 23,606 %.

We kindly invite to check this question on percentages: brainly.com/question/15469506

3 0
2 years ago
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