Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since
<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0
and
<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0
it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.
Answer:
The answer is "0.6227 and 0.5971".
Step-by-step explanation:
Answer:
x = 22 (see explanation!)
Step-by-step explanation:
Just with any algebraic equation, you will want to isolate the variable (x). Here's a step-by-step to show you how it's done:
1/7(x + 6) = 4
Multiply by 7 to get rid of the 1/7 (since 7 * 1/7 = 7/7 = 1)
7*1/7(x+6) = 7*4
x+6 = 28
Now, subtract 6 from both sides to isolate x:
x + 6 - 6 = 28 - 6
Finally:
x = 22
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