Answer:
In 5040 ways.
Step-by-step explanation:
To solve this problem we will use combination without repetition which means:
C ( n k) = (n₁ k₁) (n₂ k₂) (n₃ k₃) = (4 3) (9 2) (7 3) =
(4 · 3 · 2 / 3 · 2 · 1) (9 · 8 / 2 · 1) (7 · 6 · 5 / 3 · 2 · 1) = 4 · 36 · 35 = 5040
It can be done in 5040 ways.
God with you!!!
First one
remember that all triangles internal angles (the 3 at the vertices) add to 180
we want BCD
we know BAD already
and ABC is a right angle
the measure of BDA is just there to throw us off
so
all adds to 180
BAD+ABC+BCD=180
59+90+BCD=180
149+BCD=180
minus 149 both sides
BCD=31
BCD=31 degrees
2nd problem
all angles add to 180 degrees
so
CAB+ABC+BCA=180
6x+147+2x+78+126+x=180
6x+2x+x+147+78+126=180
9x+351=180
minus 251 both sides
9x=-171
divide both sides by 9
x=-19
x=-19 degrees
Answer:
6root2
Step-by-step explanation:
3-1,5-1. (2,4)
R=root(4+16). =6root 2
3.10+1.40= 4.50 nearest tenth