First one remember that all triangles internal angles (the 3 at the vertices) add to 180 we want BCD we know BAD already and ABC is a right angle the measure of BDA is just there to throw us off
so
all adds to 180 BAD+ABC+BCD=180 59+90+BCD=180 149+BCD=180 minus 149 both sides BCD=31 BCD=31 degrees
2nd problem all angles add to 180 degrees so CAB+ABC+BCA=180 6x+147+2x+78+126+x=180 6x+2x+x+147+78+126=180 9x+351=180 minus 251 both sides 9x=-171 divide both sides by 9 x=-19 x=-19 degrees
