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3 years ago

15

Which set of ordered pairs represents a function?

2 answers:

musickatia [10]3 years ago

7 0

Answer:

{(0,2), (-9,7), (-6, -1), (-2,2)}

Step-by-step explanation:

You can see if points are a function by seeing if the first value in the parenthesis (X value) and if they are the same, the points are not a function. The only points where the first value in the parenthesis are not the same is in the fourth set of points.

horsena [70]3 years ago

4 0

Answer:

The last one

Step-by-step explanation:

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WINSTONCH [101]

In general the binomial expansion is

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So in our case, because we want ascending powers of x we'll write,

$(-3x + 1)^{11} = {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9 + {11 \choose 3 } (-3x)^3 1^8 + ...$

We need to calculate the binomial coefficients:

${11 \choose 0} = 1$

${11 \choose 1} = 11$

${11 \choose 2} = \dfrac{11 \times 10}{2} = 55$

${11 \choose 3} = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165$

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$(1-3x)^{11} = 1 -33 x + 495 3x^2 - 4455 x^3+ ...$

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3 years ago