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kherson [118]
3 years ago
14

Hi can some one help me find AB​

Mathematics
1 answer:
Bond [772]3 years ago
8 0

Answer:

5.5 or 5 1/2

Step-by-step explanation:

In order to solve this problem, we first need to set up an equation. Line AB is tangent to circle P. So is line AC. Because these two tangent lines come together at a point, they are congruent, or equal to each other. Now that we know this, we can set up an equation in order to solve for the value of y.

3y + 4 = 11y

Now solve for y.

- 3y       - 3y

4 = 8y

÷8   ÷8

y = 0.5 or 1/2

Now that we know what the value of y is, we can plug that number into the AB equation to figure out what the measurement of line AB is.

3(0.5) + 4 =

1.5 + 4 =

5.5 or 5 1/2

We now know the measurement of line AB. I hope this helps and isn't too confusing. Please let me know if you need any more help. Good luck!

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A building's basement is 12 feet below ground. If the total length of the building from basement to roof is 62 feet, what is the
Effectus [21]

Answer:

62-12=50

Step-by-step explanation:

hope that helps!

5 0
3 years ago
Solve for t. <br><br> 4 - 2t = 2
OleMash [197]

Answer:

t = 1

Step-by-step explanation:

1) Subtract 4 from both sides so you get -2t = -2

2) Divide both sides by 2 so you get t = 1

6 0
4 years ago
Read 2 more answers
The thicknesses of 81 randomly selected aluminum sheets were found to have a variance of 3.23. Construct the 98% confidence inte
Yuliya22 [10]

Answer:

The confidence interval for the population variance of the thicknesses of all aluminum sheets in this factory is Lower limit = 2.30, Upper limit = 4.83.

Step-by-step explanation:

The confidence interval for population variance is given as below:

[(n - 1)\times S^{2}  /  X^{2}  \alpha/2, n-1 ] < \alpha < [(n- 1)\times S^{2}  / X^{2} 1- \alpha/2, n- 1 ]

We are given

Confidence level = 98%

Sample size = n = 81

Degrees of freedom = n – 1 = 80

Sample Variance = S^2 = 3.23

X^{2}_{[\alpha/2, n - 1]}   = 112.3288\\\X^{2} _{1 -\alpha/2,n- 1} = 53.5401

(By using chi-square table)

[(n – 1)*S^2 / X^2 α/2, n– 1 ] < σ^2 < [(n – 1)*S^2 / X^2 1 -α/2, n– 1 ]

[(81 – 1)* 3.23 / 112.3288] < σ^2 < [(81 – 1)* 3.23/ 53.5401]

2.3004 < σ^2 < 4.8263

Lower limit = 2.30

Upper limit = 4.83.

8 0
3 years ago
What is an equation in point-slope form of the line that passes through (-3,-1) and has a slope of 2?
IceJOKER [234]
The answer is the letter C
5 0
3 years ago
I REALLY NEED HELP PLEASE!
zhuklara [117]

Answer:

The answer to that question is b

Step-by-step explanation:

6 0
3 years ago
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