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3 years ago

Math PLEASE HELP IM SO CONFUSED IM ATTACHING THE SLIDES!!!!

Mathematics

1 answer:

slavikrds [6]3 years ago

4 0

Answer:

x = 19, TS = 22

Step-by-step explanation:

Use ratios to solve for x. Corresponding sides have same ratio.

(x + 5)/30 = (36 - 20)/20
(x + 5)/30 = 16/20 = 4/5
5(x + 5) = 4(30)
5x + 25 = 120
5x = 95
x = 19

(5x - 2)/(3x + 1) = 39/26
(5x - 2)/(3x + 1) = 3/2
2(5x - 2) = 3(3x + 1)
10x - 4 = 9x + 3
10x - 9x = 3 + 4
x = 7

TS = 3x + 1 = 3(7) + 1 = 22

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– A BOX CONTAINS 9 RED AND 2 BLUE MARBLES. IF YOU SELECT

Doss [256]

The odds against selecting a red marble is =2/11

<h3>Calculation of probability</h3>

The number of marbles which were red = 9

The number of marbles which were blue = 2

The total amount of marbles in the Box = 11

When one marble is picked at random from the box, the odds against selecting a red marble can be gotten through the blue marble.

That is, the number of blue marble/ total marble

= 2/11

Learn more about probability here:

brainly.com/question/24756209

#SPJ1

7 0

1 year ago

Which values of a and b make the following equation true? (5x7y2)(-4x4y5)=-20xayb

Kaylis [27]

Answer:

The values of a and b are a = 11 , b = 7

Step-by-step explanation:

* Lets explain how to solve the problem

* In the exponential functions we have some rules

1- In multiplication if they have same base we add the power

# Ex: b^m × b^n = b^(m + n) ⇒ b is the base , m and n are the powers

2- In division if they have same base we subtract the power

# Ex: b^m ÷ b^n = b^(m – n) ⇒ b is the base , m and n are the powers

3- If we have power over power we multiply them

# Ex: (b^m)^n = b^(mn) ⇒ b is the base , m and n are the powers

* Lets solve the problem

∵ The equation is $(5x^{7}y^{2})(-4x^{4}y^{5})=-20x^{a}y^{2}$ ⇒ (1)

- At first multiply the coefficients

∵ -4 × 5 = -20

- Multiply the base x

∵ $(x^{7})(x^{4})=x^{7+4}=x^{11}$

- Multiply the base y

∵ $(y^{2})(y^{5})=y^{2+5}=y^{7}$

∴ $(5x^{7}y^{2})(-4x^{4}y^{5})=-20x^{11}y^{7}$ ⇒ (2)

- By comparing (1) and (2)

∴ a = 11 and b = 7

* The values of a and b are a = 11 , b = 7

5 0

3 years ago

Read 2 more answers

Let A = {June, Janet, Jill, Justin, Jeffrey, Jelly}, B = {Janet, Jelly, Justin}, and C = {Irina, Irena, Arena, Arina, Jelly}. Fi

Hoochie [10]

Answer:

{June, Janet, Jill, Justin, Jeffrey, Jelly,Irina, Irena, Arena, Arina, }

Step-by-step explanation:

A ∪ C

This means union so we join the sets together

A = {June, Janet, Jill, Justin, Jeffrey, Jelly} + C = {Irina, Irena, Arena, Arina, Jelly}

A U C = {June, Janet, Jill, Justin, Jeffrey, Jelly,Irina, Irena, Arena, Arina, Jelly}

We get rid of repeats

A U C = {June, Janet, Jill, Justin, Jeffrey, Jelly,Irina, Irena, Arena, Arina, }

5 0

4 years ago

t hits the square dartboard shown below at a random point. Find the probability that the dart lands in the shaded circular regio

masha68 [24]

Given:

Required:

To find the probability that the dart land will be in the shaded region.

Explanation:

Area of the circle is given by the formula:

$A=\pi r^2$

Where r = radius

Thus the area of the circular region

$\begin{gathered} =(3.14)\times(2)^2 \\ =3.14\times4 \\ =12.56\text{ square in.} \end{gathered}$

The area of the square is given by the formula:

$=(side)^2$

Thus the area of the given square

$\begin{gathered} =(6)^2 \\ =36\text{ square in.} \end{gathered}$

The probability of an event is given by the formula:

$P=\frac{number\text{ of possible outcomes}}{Total\text{ number of outcomes}}$

The probability that the dart land will be in the shaded region

$=\frac{Area\text{ of the shaded region}}{Area\text{ of the square}}$

Thus probability

$\begin{gathered} P=\frac{12.56}{36} \\ P=0.3488 \\ P=0.349 \end{gathered}$

Final answer:

Thus the probability that the dart land will be in the shaded region is 0.349.

6 0

1 year ago

Ben is three times as old as Kate. Kate is 6 years older than Jill. Jill is J years old. What is the combined age of the three p

harkovskaia [24]

Answer:

the combined age of the three people is

5 J + 24

Step-by-step explanation:

Jill (J)

Kate (J+6)

Ben 3(J+6)

J + (J+6) + 3(J+6)

J+J + 6 +3 J +18

5 J + 24

8 0

3 years ago