Ask question

Ask question

All categories

3 years ago

6

If g(x)= x^2 -x, find g(-1)+4

1 answer:

NikAS [45]3 years ago

6 0

Answer:

-g + 4

Step-by-step explanation:

You might be interested in

I will give you 50 if you helped me thanks

Nimfa-mama [501]

Answer:

it's 40!

10 x 10 = 100

10 x 4 = 40

6 x 10 = 60

and 6 x 4 = 24 !!

5 0

3 years ago

Read 2 more answers

A fruit fly experiment starts with 600 flies. If the number of flies after x days is given by the function P(x)=600e^0.3x, how m

slega [8]

Since ln(x) is the inverse of e^x and we want to find out when P(x)=1000, we will substitute P(x) by 1000 and then solve for x days.

1600e^0.3x = 1000

Divide 600 for both sides you will get:

5/3 = e^0.3x

Multiply ( ln ) for both sides and then divide by 0.3.

(ln 5/3)/(0.3) = x

x = 1.7

So there will be 1000 flies in approximately 1.7 days

6 0

4 years ago

9966 [12]

The answer will be x=23

6 0

2 years ago

What is the approximate volume of the oblique cone? Use π ≈ 3.14 and round to the nearest tenth. 117.8 cubic units 141.3 cubic u

Tom [10]

Answer:

The answer is 235.5 :)

Step-by-step explanation:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago