Answer:
2g + 2f = 5.16
7g + 9f = 21.24
Step-by-step explanation:
Let
Gala = g ; Fuji = f ; jazz = j
g + f + j = 5.16 - - - (1)
j = g + f - - - (2)
From (1):
g + f + g + f = 5.16
2g + 2f = 5.16 - - - (3)
Total pound picked by Tanner = 12
3 Pounds of g ; 5 pounds of f
j = 12 - (5 +3) = 4 pounds
3g + 5f + 4j = 21.24 - - - (4)
3g + 5f + 4(g + f) = 21.24
3g + 5f + 4g + 4f = 21.24
7g + 9f = 21.24 - - - - - (5)
You should be able to multiply 91 by 8 to get the sum of the first 8 tests, then add the score on the 9th test. Then to get the average of the sum of the 9 tests you need to divide it by 9.
((91*8)+78)/9=89.555555555555.... So, 90%
Answer:
These are simultaneous equations.They have to be solved like this:
2x-y=3 -y=3-2x 2x-3= -x
y= -x y= -(3-2x) 3x= 3
y=2x-3 x=1
Step-by-step explanation:
The value of x equals to 1
Answer:
Option A is correct
The function
has real zeroes at x =-10 and x =-6
Explanation:
Given: The real zeroes or roots are x = -10, and x = -6
To find the quadratic function of degree 2.
where α,β are real roots. ....[1]
Here, α= -10 and β= -6
Sum of the roots:
α+β = -10+(-6) = -10-6 = -16
Product of the roots:
αβ = (-10)(-6)= 60
Substitute these value in equation [1] we have;
![x^2-(-16)x+60 = x^2+16x+60](https://tex.z-dn.net/?f=x%5E2-%28-16%29x%2B60%20%3D%20x%5E2%2B16x%2B60)
Therefore, the quadratic function for the real roots at x =-10 and x =-6 ;
![x^2+16x+60](https://tex.z-dn.net/?f=x%5E2%2B16x%2B60)