Question

5) If Oskar bisects the diameter of a circle, what is he trying to construct?

Answer 1

Answer:

Center = (5,-3) and radius = 7

Step-by-step explanation:

(5) If Oskar bisects the diameter of a circle, what is he trying to construct the radius of the circle.

(6) The given equation is :

$(x-5)^2+(y+3)^2=49$

The general equation of circle is given by :

$(x-a)^2+(y-b)^2=r^2$ ...(1)

Where

(a,b) are the coordinates of the centre and r is the radius.

The given equation can be written as :

$(x-5)^2+(y+3)^2=7^2$ ..(2)

Comparing equation (1) and (2) we get :

a = 5, b = -3 and r = 7

So,

Center = (5,-3) and radius = 7

Hence, this is the required solution.