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sergejj [24]
2 years ago
9

Is 3/4 proportional to 6/15 ​

Mathematics
1 answer:
LiRa [457]2 years ago
4 0

answer:

no

step-by-step explanation:

step one- cross multiply

3*15=4*6

step two- multiply

3*15=45 4*6=24

step three- simplify

45=24

45 and 24 aren't equal, therefore 3/4 and 6/15 are not proportional

good luck :)

i hope this helps

have a nice day !!

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Answer:

0.466 degree is the. answer

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3 years ago
Which decimal is equivalent to 10/3
Aneli [31]
3.3333333 repeating
Take 10 and divide it by 3
6 0
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<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{
Jlenok [28]

Answer:

x>2

Step-by-step explanation:

When given the following inequality;

(x^2+x-3):(x^2-4)\geq1

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

\frac{x^2+x-3}{x^2-4}\geq1

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

\frac{x^2+x-3}{x^2-4}-1\geq0

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0

Perform the operation on the other side distribute the negative sign and combine like terms;

\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0

Factor the equation so that one can find the intervales where the inequality is true;

\frac{x+1}{(x-2)(x+2)}\geq0

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

-1, 2, -2

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

x\leq-2\\-2

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

x\leq-2   -> negative

-2   -> neagtive

-1\leq x   -> neagtive

x>2   -> positive

Therefore, the solution to the inequality is the following;

x>2

6 0
3 years ago
Solve this linear system by graphing <br> x-y=6 <br> 2x=12+2y
lys-0071 [83]
You need to isolate the variables. For the first equation add x to both sides, which leaves you with y.

For the second equation, divide each side by 2 leaving you with
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5 0
3 years ago
A vacuum had been marked down by 20% and solf for $250. What was the original price of the vacuum?
igomit [66]

Answer:

The original price was $312.50

Step-by-step explanation:

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Let's set up an equation.

80/100 of x = 250

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Divide both sides by 0.8.

x = 312.50

The original price was $312.50

Hope this helps!

7 0
3 years ago
Read 2 more answers
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