All categories

3 years ago

What is it called when the variable dosnt have an answer?

Mathematics

2 answers:

ipn [44]3 years ago

4 0

This would be called an interval variable. Hope this helped, could I possibly get brainliest?

maks197457 [2]3 years ago

3 0

Hello.

The answer is : No soultion.

No solution would mean that there is no answer to the equation. It is impossible for the equation to be true no matter what value we assign to the variable.

Have a nice day

You might be interested in

1<br> If f(x) = 3x + 2 and g(x)=x+1, which expression is equivalent to (fog)(x)?

swat32

Answer:

(3x+2)^2+1

Step-by-step explanation:

(f°g)(x) =g(f(x)) =g(3x+2)=(3x+2)^2 +1

6 0

3 years ago

Read 2 more answers

Help!!! I will give brainliest.

iVinArrow [24]

4x - 4y = -36
3x + 4y = 8
7x = -28
/7 /7
x = -4

-4 - y = -9
+4 +4
-y = -5
/-1 /-1
y = 5

(-4 , 5)

7 0

3 years ago

What is the value of m squared minus 2 m n + n squared for m = negative 2 and n = 4?

topjm [15]

The answer is 36. Check work

6 0

3 years ago

Read 2 more answers

1) A traditional die is a cube with each of its six sides representing the numbers from 1 to 6. Mr. Dicey customized a die by re

liraira [26]

Answer:

1) $\frac{2}{5}$

2) 49.225

3) $\frac{7}{2}$

Step-by-step explanation:

1) To find the expected value of the dice we can use the following equation:

$E(x)=x_{1}*P(x_{1})+x_{2}*P(x_{2})+...+x_{n}*P(x_{n})$

So in our problem the values x will be: 1/1, 1/2, 1/3, 1/4, 1/5 and 1/6 and the probavility for all values is 1/6 so the expected values will be: $E(x)=(\frac{1}{1} *\frac{1}{6}) +(\frac{1}{2} *\frac{1}{6}) +(\frac{1}{3} *\frac{1}{6})+(\frac{1}{4} *\frac{1}{6})+(\frac{1}{5} *\frac{1}{6})+(\frac{1}{6} *\frac{1}{6})$

$E(x)=0.167+0.083+0.056+0.042+0.033+0.028=0.409\approx \frac{2}{5}$

2) To find the variance of the expected values we can use the equation:

$Var(x)=\frac{\sum_{i=1}^{n}(x_{i}-\overline{x})^{2} }{n}$

So for our problem will be:

$Var(x)=\frac{(3-10.5)^2+(4-10.5)^2+(17-10.5)^2+(18-10.5)^2}{4}$

$Var(x)=\frac{56.25+42.25+42.25+56.25}{4}$ $Var(x)=\frac{196.9}{4}=49.225$

3) To find the expected value of the dice we can use the following equation:

$E(x)=x_{1}*P(x_{1})+x_{2}*P(x_{2})+...+x_{n}*P(x_{n})$

So in our problem the values x will be: 1, 2, 3, 4, 5 and 6 and the probavility for all values is 1/6 so the expected values will be: $E(x)=(1*\frac{1}{6}) +(2 *\frac{1}{6}) +(3 *\frac{1}{6})+(4 *\frac{1}{6})+(5 *\frac{1}{6})+(6 *\frac{1}{6})$

$E(x)=0.17+0.33+0.5+0.67+0.83+1=3.5\approx \frac{7}{2}$

7 0

3 years ago

I really need this done today please help PLEAASSSEEE

Fantom [35]

Answer:

A and C

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers