Answer:
Step-by-step explanation:
As per Janayda,
From the figure attached,
In ΔTRQ,
m∠TRQ + m∠RQT + m∠QTR = 180°
25° + m∠RQT + 35° = 180°
m∠RQT = 180° - 60°
m∠RQT = 120°
Since, m∠RQT + m∠PQT = 180° [Linear pair of angles]
m∠PQT = 180° - m∠RQT
= 180° - 120°
= 60°
In right angled triangle TPQ,
m∠TPQ + m∠PQT + m∠PTQ = 180°
90° + 60° + m∠PTQ = 180°
m∠PTQ = 180° - 150°
= 30°
Similarly, other angles can also be evaluated from the given information.
In ΔQTP and ΔNTP,
TP ≅ TP [Reflexive property]
NP ≅ PQ [Given]
ΔQTP ≅ ΔNTP [By LL postulate for congruence]
Therefore, Janayda is correct.
While Sirr is incorrect.
Since, there is not the enough information to prove ΔRTQ and ΔMTN equal, Isabelle is incorrect.
the answer is b i’m pretty sure
Let's say the numbers are "a" and "b"
now, we know one of them is 7 more than the other, so hmmm let's say "b" is 7 more than "a", so b = a + 7
the difference of their squares is 161, alrite

and surey you know how much that is
now, what's "b"? well, b = a + 7
Answer:
227.5
Step-by-step explanation:
trust meh ._.
Answer:
sin60 = p/h
√3/2 = 2/x
x = 4/√3 × √3/√3 = 4√3/3unit.