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artcher [175]
3 years ago
11

Solve for the x in the equation

625" id="TexFormula1" title="x + 3x + 5x + 7x + ...49x = 625" alt="x + 3x + 5x + 7x + ...49x = 625" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Flauer [41]3 years ago
7 0

Answer:

x=1

Step-by-step explanation:

x+3x+5x+7x+...+49x=625

(1+3+5+7+...+49)x=625    (1)

now consider s= 1+3+5+7+...+49

a=1

d=3-1=2

l=49

l=a+(n-1)d

49=1+(n-1)2

49-1=(n-1)2

48/2=n-1

n-1=24

n=24+1=25

s=n/2*(a+l)

s=25/2(1+49)

x=25/2×50

s=25×25=625

from (1)

625 x=625

x=625/625=1

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